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Andre45 [30]
3 years ago
9

A region R in the xy-plane is given. Find equations for a transformation T that maps a rectangular region S in the uv-plane onto

R, where the sides of S are parallel to the u- and v- axes. (Let u play the role of r and v the role of θ. Enter your answers as a comma-separated list of equations.) R lies between the circles x^2 + y^2 = 1 and x^2 + y^2 = 3 in the first quadrant
Mathematics
1 answer:
muminat3 years ago
7 0

Answer:

x = u\cos(v) , y = u \sin(v)

Step-by-step explanation:

For that transformation you just have to use polar coordinates, notice that when you use polar coordinates the radius is constant when the angles varies and the angle is constant when the radius varies. Therefore your transformation would be just

x = u\cos(v) , y = u \sin(v).

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find five solutions of the equation y=20x. select integers for values for x starting with -2 and ending with 2
Nataly_w [17]

Answer:

-440, -4440, -44440, -444440, -4444440

Step-by-step explanation:

First, let's find values for x which start is a -2 and end with a 2.

-22

-222

-2222

-22222

-222222

Now we can find the y value by multiplying each term by 20.

-22 --> -440

-222 --> -4440

-2222 --> -44440

-22222 --> -444440

-222222 --> -4444440

7 0
3 years ago
On a coordinate plane, A line is drawn from point Fernando to point Maria. Fountain is labeled in between the 2. Fernando is at
agasfer [191]

The location of the fountain as described in the task content is; (-1, -0.5).

<h3>What is the location of the Fountain?</h3>

According to the task content, the locations of Fernando and Maria are given as; (-4, -2) and (4,2) respectively and the ratio of division is expected to be; 5: 3.

Hence, the coordinates of the fountain can be evaluated as;

x = (4) - (4-(-4)) × (5/8) = -1.

y = 2 - (2-(-2)) × (5/8) = -0.5

Hence, it follows that the coordinates of the fountain location is; (-1, -0.5) since the fountain is closer to Fernando than Maria.

Read more on dividing lines by ratios;

brainly.com/question/21108138

#SPJ1

8 0
1 year ago
What is the cube root of 216x^9y^18?
PilotLPTM [1.2K]

Answer:

The cube root of given expression is 6x^3y^6.

Step-by-step explanation:

The given expression is

\sqrt[3]{216x^9y^{18}}

It can be written as

Use the exponent property: a^{mn}=(a^m)^n

\sqrt[3]{216x^9y^{18}}=\sqrt[3]{6^3(x^3)^3(y^6)^{3}}

\sqrt[3]{216x^9y^{18}}=\sqrt[3]{(6x^3y^6)^{3}}

\sqrt[3]{216x^9y^{18}}=6x^3y^6

Therefore the cube root of given expression is 6x^3y^6.

8 0
3 years ago
What is the value of 4 2/3 divided by 2/5
Nitella [24]
4 2/3 /2 /5
14/3 / 2/5 cross multiply 
7/3 / 1/5 multiply 7 and 5 and 3 and 1
35/3 simplify
11 2/3
6 0
3 years ago
What is the value of x?
kicyunya [14]

Answer:

(5(x-4))0

evaluate

1

Step-by-step explanation:

your answer is one i believe

6 0
3 years ago
Read 2 more answers
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