What is the conjugate? square root of 8 - square root of 9
1 answer:
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<h3>(-3j²k³)²(2j²k)³</h3>
(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.</em>
= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>
= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>
= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.</em>
= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹
Answer = 72j¹⁰k⁹
Hope this helps!
Answer:
y + 1 = -1/2(x - 8)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Algebra I</u>
Slope Formula:
Point-Slope Form: y - y₁ = m(x - x₁)
- x₁ - x coordinate
- y₁ - y coordinate
- m - slope
Step-by-step explanation:
<u>Step 1: Define</u>
f(8) = -1 → Coordinate (8, -1)
f(6) = 0 → Coordinate (6, 0)
<u>Step 2: Find slope </u><em><u>m</u></em>
- Substitute [SF]:
- Add/Subtract:
- Simplify:
<u>Step 3: Write Function</u>
<em>Substitute into general form.</em>
- Point 1: y + 1 = -1/2(x - 8)
- Point 2: y = -1/2(x - 6)