Question

What are the vertical asymptotes of the function f(x) = the quantity of 2 x plus 8, all over x squared plus 5 x plus 6?

Answer 1

Answer:

Step-by-step explanation:

Alright, lets get started.

The given rational function is :

$f(x)=\frac{2x+8}{x^2+5x+6}$

For finding the vertical asymptotes of a rational function,  we must set the denominator equal to zero.

So, equaling denominator to zero :

$x^2 +5x+6 = 0$

factoring

$(x+3)(x+2)=0$

This will give two values of x

$x=-3, x=-2$    

So, these two are vertical asymptotes   :   Answer

Hope it will help :)

Answer 2

You'd find the vertical asymptotes by seeing where the denominator equals zero; you can do so by factoring the denominator.
In this case, you can factor the denominator into (x+3)(x+2), so if you set each of those equal to zero you can find the equations of the vertical asymptotes (x=-3 and x=-2).