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VikaD [51]
3 years ago
13

What are the vertical asymptotes of the function f(x) = the quantity of 2 x plus 8, all over x squared plus 5 x plus 6?

Mathematics
2 answers:
Gre4nikov [31]3 years ago
8 0

Answer:

Step-by-step explanation:

Alright, lets get started.

The given rational function is :

f(x)=\frac{2x+8}{x^2+5x+6}

For finding the vertical asymptotes of a rational function,  we must set the denominator equal to zero.

So, equaling denominator to zero :

x^2 +5x+6 = 0

factoring

(x+3)(x+2)=0

This will give two values of x

x=-3, x=-2    

So, these two are vertical asymptotes   :   Answer

Hope it will help :)

lutik1710 [3]3 years ago
6 0
You'd find the vertical asymptotes by seeing where the denominator equals zero; you can do so by factoring the denominator.
In this case, you can factor the denominator into (x+3)(x+2), so if you set each of those equal to zero you can find the equations of the vertical asymptotes (x=-3 and x=-2).
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