Answer:
no, this is not a function
Step-by-step explanation:
i hope this helps :)
42/60, x/320. 320/60=5.33333, 42*5.33333=224. So, about 224 students would ride the bus.
Answer:
12
Step-by-step explanation:
(25-16) / h = h / 16
9/h = h/16
=144 ( 9 x 16)
h₂ = 144
h= square root 144
h= 12
To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
_____
The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.
I'm assuming you mean (a-b)^2 : (a+b)^2
a^2 + b^2 cancel out leaving
-2ab versus +2ab
Therefore (a+b)^2 is +4ab greater.
