.27 repeating.... you have to put three on the inside and 11 outside, so 11 goes into 3 zero times so put a zero at the top. Write a zero underneath and subtract 3-0 (obviously 3) and put a decimal point after the first three under the sign and the 0 above it. Add a zero after the threes decimal, and carry it down to the bottom most 3 to have 30. 11 goes into 30 two times so write a 2 at the top. Subtract the 30-22 at the bottom and get 8. Add another 0 after the 3 ( so now 3.00) and carry it to the 8 (80). 11 goes in 7 times, 77. So 7 on top and 80-77= 3 below. Add another zero to repeat process if necessary, but otherwise it repeats, just so you know ;) hope this helps
Answer:
23. 
24. 
25. 
26. 
27. 
28. 
Step-by-step explanation:
To solve these i used SOHCAHTOA

23.
Find the missing side using Tangent



24.
Find the missing side using Tangent



25.
Find the missing side using Tangent



26.
Find the missing side using Tangent



27.
Find the missing side using Tangent



28.
Find the missing side using Tangent



Answer:
Since there are 4 green bars for every 3 red bars and we are trying to find the number of red bars if there are 200 green bars, we can create the ratio:
4
x
:
3
y
Where x is equal to the number of green bars and y
is the number of red bars.
We know the number of green bars is equal to 200, so we can divide it by 4, giving us:
200
/4=50
Then we can solve for y
, the number of red bars.
// Multiple y by 50
3
⋅
50
=
150
So for every 4 green bars, there are 3 red bars.
For every 200 green bars, there are 150 red bars
Step-by-step explanation:
Answer:
√10/2x
Step-by-step explanation:
Multiply by √6 on the top and bottom to rationalize the denominator.
(√15×√6)/(√6x×√6) = √90/6x = (√9×√10)/6x = 3√10/6x = √10/2x