Answer:
12r/t
Step-by-step explanation:
Answer:
x = -3 and x = -3/2
Step-by-step explanation:
After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:
p(x) = 2x^3 + 3x^2 <u>- 18x -27</u>
p(x) = x^2(2x+3) <u>-9(2x+3)</u>
Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:
p(x) = (x^2 - 9)(2x+3)
Factor it once more because there's a difference of squares:
p(x) = (x+3)(x-3)(2x+3)
Now just plug in whatever makes the each bracket equal 0:
x = -3, x = 3, and x = -3/2
Those are your zeros.
Answer:
f(x) has moved:
4 units in the positive y direction i.e upwards
3 units in the positive x direction
Step-by-step explanation:
to get g(x), f(x) has undergone the following transformations
f(x) = x³
f1(x) = x³ + 4 (translation of 4 units in the positive y direction i.e upwards)
f2(x) = g(x) = (x-3)³ + 4 (translation of 3 units in the positive x direction i.e towards the right)
Y = 17 is not a linear function.
2x²(a-b) + x(b-a) + 6(b-a) = 2x²(a-b) - x(a-b) - 6(a-b) = (a-b)(2x²- x - 6)=
=(a-b)(2x+3)(x-2)
6x²(a-b) + x(a-b) + 12(b-a) = 6x²(a-b) + x(a-b) - 12(a-b) =(a-b)(6x²+x - 12)=
=(a-b)(3x - 4)(2x + 3)
