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3 years ago

6

Draw an area model 1.1x2.4

1 answer:

Alexus [3.1K]3 years ago

5 0

You have to draw a rectangle and label the longer side 2.4 and the shorter side 1.1

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Geometry. Find the angle

lisabon 2012 [21]

Answer:

x = 10°; Angle A = 84°

Step-by-step explanation:

Angle A + Angle B = 180

5x + 34 + 2x + 76 = 180

7x + 110 = 180

7x = 70

x = 10

Angle A: 5(10) + 34 = 50 + 34 = 84°

7 0

3 years ago

Read 2 more answers

Each set of ordered pairs represent a function. writ a rule that represents the function. can you help? (0,1) (1,3) (2,9) (3,27)

Hoochie [10]

X1-x2/y1-y2 is what you need for ordered pair

3 0

3 years ago

A rancher wants to cut a metal cylinder in half to use as a watering trough as shown below.

velikii [3]

Answer:

88.3 ft3 is the answer hope this helps!!

Step-by-step explanation:

3 0

3 years ago

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

3 years ago

Plz help it would mean a lot

lina2011 [118]

Answer:

proportional/equal

Step-by-step explanation:

doesnt need

6 0

2 years ago