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boyakko [2]
3 years ago
15

How do is solve 9/8x+7/6x

Mathematics
1 answer:
Agata [3.3K]3 years ago
5 0
They are both improper fractions once changed then can be added for ex.
9/8= 1 1/8x      7/6= 1 1/6x
anyways answer is 55/24= 2 7/24
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Add the fraction 1/2+3/18
AURORKA [14]
1/2 + 3/18 = 9/18 + 3/18 = 12/18 = 2/3

3/45 + 6/50 = 1/15 + 3/25 = 5/75 + 9/75 = 14/75
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Writeanequationforthelinethatpassesthrough(4,-3)and has a slope of 3.
djyliett [7]

Answer:

x+y=1 (if x=4 )

4+y=1

y=1-4

y=-3

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The graph shows the function of f(x)=(3.5)^x
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The one that passes through the origin. That one in the lower left part.
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Solve the following equation by factoring:9x^2-3x-2=0
olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}

Step-by-step explanation:

Original quadratic equation is 9x^{2}-3x-2=0

Divide both sides by 9:

x^{2} - \frac{x}{3} - \frac{2}{9}=0

Add \frac{2}{9} to both sides to get rid of the constant on the LHS

x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}  ==> x^{2} - \frac{x}{3}=\frac{2}{9}

Add \frac{1}{36}  to both sides

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}

This simplifies to

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = \frac{1}{6}\right) we can see that

\left(x - \frac{1}{6}\right)^2 = x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}

So

\left(x - \frac{1}{6}\right)^2=\frac{1}{4}

Taking square roots on both sides

\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}

So the two roots or solutions of the equation are

x - \frac{1}{6}=-\sqrt{\frac{1}{4}}  and x - \frac{1}{6}=\sqrt{\frac{1}{4}}

\sqrt{\frac{1}{4}} = \frac{1}{2}

So the two roots are

x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}

and

x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}

7 0
1 year ago
Are the slopes 1/4 and -1/4 parallel, perpendicular, or neither?
anyanavicka [17]
-1/4 is not = -1 / 1/4 ( its = -4)  so its neither .
6 0
3 years ago
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