Answer:
A. 4(x + 8) = 56
Step-by-step explanation:
the correct equation would be 4(x + 8) = 56
because we need to find the number of hours on Saturday, since there Sheldon gets paid $4 per hour, we must subtract the amount Sheldon made on Sunday by the total he made and then divide that by 4 to get the number of hours on Saturday
$4 = number of dollars per hour
$56 = total on Saturday and Sunday
8 hours = Number of hours babysat on Sunday
x = hours spent on Saturday
4(x + 8) = 56
Step 1: Simplify both sides of the equation.
4(x + 8) = 56
(4)(x) + (4)(8) = 56(Distribute)
4x + 32 = 56
Step 2: Subtract 32 from both sides.
4x + 32 − 32 = 56 − 32
4x = 24
Step 3: Divide both sides by 4.
4x/4 = 24/4
x = 6
To check if this is correct, we add the amount Sheldon earned on Saturday to the amount he earned on Sunday, which is
6(4) + 8(4) = 56
24 + 32 = 56
56 = 56
or you could substitute the answer in the problem
4(6 + 8) = 56
Distribute
24 + 32 = 56
Simplify
56 = 56
Answer:
B 41.4
Step-by-step explanation:
complete Pythagoras for general triangles :
c² = a² + b² - 2ab×cos(C)
with "c" being the side opposite of the angle C.
=>
8² = 10² + 12² - 2×10×12×cos(C)
64 = 244 - 240×cos(C)
240×cos(C) = 244 - 64 = 180
cos(C) = 180/240 = 18/24 = 3/4 = 0.75
C = 41.40962211... ≈ 41.4
Answer:
18 minutes
Step-by-step explanation:
A = A₀ (½)^(t / T)
where A is the final amount,
A₀ is the initial amount,
t is the time,
and T is the half life.
A = 140 when t = 10. Solve for the half life:
140 = 700 (½)^(10 / T)
0.2 = ½^(10 / T)
log 0.2 = (10 / T) log 0.5
10 / T = 2.32
T = 4.31
When A = 40, t is:
40 = 700 (½)^(t / 4.31)
0.057 = ½^(t / 4.31)
log 0.057 = (t / 4.31) log 0.5
t / 4.31 = 4.13
t = 17.8
Rounded to the nearest whole number, it takes 18 minutes.
That is a 45 45 90 triangle.
The legs of such a triangle equal the hypotenuse divided by the sq root of 2
So each leg equals 125.5 cm divided by
<span>
<span>
<span>
1.4142135624
</span>
</span>
</span>
which equals
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<span>
<span>
88.7419010389
</span>
</span>
</span>
or to the nearest 100th of a centimeter:
88.74