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ASHA 777 [7]
3 years ago
11

Antoine has $18.20 to spend on some oranges and a pumpkin. Oranges cost

Mathematics
1 answer:
Oksana_A [137]3 years ago
7 0

Answer:

10 pounds

Step-by-step explanation:

You forgot the inequality sing, but since Antoine can't spend more than $18.20, I am positive that the sign is \leq (Antony can spend $18.20 or less than $18.20).

Therefore, our inequality is: 1.30x+5.20\leq 18.20

where x is the pounds of oranges

Let's solve step-by-step to find how many pounds of oranges he can buy

Step 1. Subtract 5.20 fro both sides of the inequality

1.30x+5.20-5.20\leq 18.20-5.20

1.30x\leq 13

Step 2. Divide both sides of the inequality by 1.30

\frac{1.30x}{1.30} \leq \frac{13}{1.30}

x\leq 10

We can conclude that Antony can buy 10 pounds of oranges.

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<h3>              f(x) = x - 6</h3><h3>             g(x) = x - 5</h3>

Step-by-step explanation:

\dfrac{x^2-8x+12}{x^2-7x+10}\\\\x^2-7x+10\ne0\ \iff\ x=\frac{7\pm\sqrt{49-40}}{2}\ne0\ \iff\ x\ne5\ \wedge\ x\ne2\\\\\\\dfrac{x^2-8x+12}{x^2-7x+10}=\dfrac{x^2-2x-6x+12}{x^2-2x-5x+10}=\dfrac{x(x-2)-6(x-2)}{x(x-2)-5(x-2)}=\\\\\\ =\dfrac{(x-2)(x-6)}{(x-2)(x-5)}=\dfrac{x-6}{x-5}\\\\\\f(x)=x-6\\\\g(x)=x-5

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3 years ago
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What is the y -value of the solution to the system of equations shown? 6x=3y−24 4x+5y=−2
Vlada [557]

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Graph the line with slope <br> −3/4<br><br> passing through the point <br> , (3,3)
Nookie1986 [14]
Y = mx + b
slope(m) = -3/4
(3,3)....x = 3 and y = 3
now we sub and find b, the y int
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so ur equation is : y = -3/4x + 21/4

ur y int = (0,21/4) or (0,5.25)

ur x int can be found by subbing in 0 for y and solving for x
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0 = -3/4x + 21/4
3/4x = 21/4
x = 21/4 * 4/3
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so plot ur points (7,0) and (0,5.25)....now start at (0,5.25) and since the slope is -3/4, come down 3 spaces and go to the right 4 spaces, then down 3, and to the right 4 and u will eventually cross the x axis at (7,0)




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