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8090 [49]
3 years ago
15

Solve -2(5x – 3) = 41.

Mathematics
1 answer:
White raven [17]3 years ago
3 0

Answer:

x = -3.5

Step-by-step explanation:

-2(5x – 3) = 41

-10x + 6 = 41

-10x + 6 - 6 = 41 - 6

-10x/-10 = 35/-10

x = -3.5

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Branilest and 30 point please answer
Lynna [10]

Answer:

<em>Addition Property of Equality</em>

Step-by-step explanation:

<u>System of Equations</u>

When two equations are given and two variables are unknown in both equations, then we can solve the system in several ways.

One method consists in adding both equations term by term and eliminate one of the variables. That property is called the addition of equalities. Let's consider the equations given in the problem:

5x+4y=-2\\2x-4y=6

If we add both equations, we have

5x+4y+2x-4y=-2+6

Simplifying

7x=4

By adding both equations we managed to eliminate the variable y and could easily find the value of x

x=4/7

Answer: Addition Property of Equality

7 0
4 years ago
Twice the complement of angles A is 40 less than the supplement of angle A. Find the measure of angle A
Serggg [28]
Complement adds to 90
complement of A is 90-A


supplement is adds to 180
supplemetn of A is 180-A

2(90-A) is -40+180-A

2(90-A)=-40+180-A
2(90-A)=140-A
distribute
180-2A=140-A
add 2A to both sides
180=140+A
minus 140 both sides
40=A

A=40 degres
4 0
3 years ago
Read 2 more answers
HELP! Find the value of sin 0 if tan 0 = 4; 180 &lt; 0&lt; 270
BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

\large \boxed{sin \theta = tan \theta cos \theta} \\  \large \boxed{tan^{2}  \theta + 1 =  {sec}^{2} \theta}

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

\large{ {4}^{2}  + 1 =  {sec}^{2} \theta } \\  \large{16 + 1 =  {sec}^{2} \theta } \\  \large{ {sec}^{2}  \theta = 17}

As we know, sec²θ = 1/cos²θ.

\large \boxed{sec \theta =   \frac{1}{cos \theta} } \\  \large \boxed{ {sec}^{2}  \theta =  \frac{1}{ {cos}^{2}  \theta} }

And thus,

\large{  {cos}^{2}  \theta =  \frac{1}{17}}   \\ \large{cos \theta =  \frac{ \sqrt{1} }{ \sqrt{17} } } \\  \large{cos \theta =  \frac{1}{ \sqrt{17} }  \longrightarrow  \frac{ \sqrt{17} }{17} }

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

\large{cos \theta =   \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta =  -  \frac{ \sqrt{17} }{17}}

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

\large{sin \theta = 4 \times ( -  \frac{ \sqrt{17} }{17}) } \\  \large{sin \theta =  -  \frac{4 \sqrt{17} }{17} }

Answer

  • sinθ = -4sqrt(17)/17 or A choice.
4 0
3 years ago
Explain how you can find the volume of the figure below. Then, solve- what is the volume of the figure? Make sure to include you
mote1985 [20]

Answer: a) The figure can be reasonably divided into two geometries:

• a rectangular prism

• a hemisphere.

b) The volume of the rectangular prism is given by

  V = lwh

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The volume of the hemisphere is given by

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  V = (2π/3)(3 cm)³ = 18π cm³

c) The total volume of the figure is

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  V = 200 cm³ + 18π cm³

  V ≈ 256.549 cm³

Step-by-step explanation:

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vodomira [7]

Answer:

4.) 12

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Step-by-step explanation:

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