The answer to the question
Answer:
Let coordinates of vertex D be (x,y)
In parallelogram diagonals are bisect each other.
∴ Mid-point of AC= Mid-point of BD
⇒ (
2
3+(−6)
,
2
−4+2
)=(
2
−1+x
,
2
−3+y
)
⇒ (
2
−3
,
2
−2
)=(
2
−1+x
,
2
−3+y
)
⇒ (
2
−3
,−1)=(
2
−1+x
,
2
−3+y
)
Now,
⇒
2
−3
=
2
−1+x
⇒ −6=−2+2x
⇒ −4=2x
∴ x=−2
⇒ −1=
2
−3+y
⇒ −2=−3+y
⇒ 1=y
∴ y=1
∴ Coordinates of vertex D is (−2,1)
Answer:
The equation of the line is 2 x - y + 5 = 0.
Step-by-step explanation:
Here the given points are A( 1, 7) & B( -3, - 1) -
Equation of a line whose points are given such that
(
) & (
)-
y -
=
( x -
)
i.e. <em> y - 7=
( x- 1)</em>
<em> y - 7 =
( x -1)</em>
<em> y - 7 = 2 ( x - 1) </em>
<em> y - 7 = 2 x - 2</em>
<em> 2 x - y + 5 = 0</em>
Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1) is 2 x - y + 5 = 0.
Answer:
$12.25
Step-by-step explanation:
Step 1:
$294 : 24 Ratio
Step 2:
$294 ÷ 24 Divide
Answer:
$12.25
Hope This Helps :)
Answer:

Step-by-step explanation:

Distribute -3 through the parentheses
Similarly, Distribute 4 through the parentheses
⇒
Collect like terms
⇒
Calculate
⇒
Move 33 to right hand side and change it's sign
⇒
Calculate
⇒
Hope I helped!
Best regards!!