Answer:
segment AB over segment A double prime B double prime = the square root of 13 over 2 times the square root of 13
Step-by-step explanation:
Triangle ABC has vertices at points A(-3,3), B(1,-3) and C(-3,-3).
1. Reflection over x = 1 maps vertices A, B and C as follows
- A(-3,3)→A'(5,3);
- B(1,-3)→B'(1,3);
- C(-3,-3)→C'(5,-3).
2. Dilation by a scale factor of 2 from the origin has the rule
(x,y)→(2x,2y)
So,
- A'(5,3)→A''(10,6);
- B'(1,3)→B''(2,6);
- C'(5,-3)→C''(10,-6)
See attached diagram for details
Note that
so
15:33
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Answer:
x + 1
y = 9
Step-by-step explanation:
In order to solve this question we need to represent "y "in terms of "x" in the first equation, and the plug in the "y" value in the first equation into the second one. Luckily for us in the first equation it already shows what "y" is equal to in terms of "x" (based on the first equation y = -x + 10). Now we just need to plug in the value that we got instead of "y" in the second equation, and so we get....
y = 7x + 2
(plug in the y value and get the following ….)
-x + 10 = 7x + 2
(now just solve the following equation)
-x + 10 + x = 7x + 2 + x
10 = 8x + 2
10 - 2 = 8x + 2 - 2
8 = 8x
8/8 = 8x/8
1 = x
Now that we know the value of "x", all we need to do now is substitute the value of "x" into any of the equations and we will get the value of "y". So we do the following.....
y = 7x + 2
y = 7(1) + 2
y = 7 + 2
y = 9
table A because they are the fame proportion
