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3 years ago

Please help, very confused

Mathematics

2 answers:

miss Akunina [59]3 years ago

6 0

Answer:

-3x + 8y = -5

6x + 2y = -8

Set the equations to a common variable.

-3x + 8y = -5 → 8y = 3x - 5 → y = 3/8x - 5/8

6x + 2y = -8 → 2y = -6x - 8 → y = -3x - 4

Set the equations equal to each other.

3/8x - 5/8 = -3x - 4

Combine like terms.

3x + 3/8x = -4 + 5/8

3.375x = -3.375

Divide by 3.375

x = -1

Plug x back in to find y.

-3x + 8y = -5

-3(-1) + 8y = -5

3 + 8y = -5

8y = -8

y = -1

answer: (-1, -1)

3x + 2y = -16

-3x - 8y = 46

Set the equations to a common variable.

3x + 2y = -16 → 2y = -3x - 16 → y = -3/2x - 8

-3x - 8y = 46 → -8y = 3x + 46 → y = -3/8x - 23/4

Set the equations equal to each other.

-3/2x - 8 = -3/8x - 23/4

Combine like terms.

-9/8x = 9/4

-1.125x = 2.25

Divide by -1.125

x = -2

Plug x back in to find y.

3(-2) + 2y = -16

-6 + 2y = -16

2y = -10

y = -5

answer: (-2, -5)

cluponka [151]3 years ago

4 0

Question 1- (-1,-1)

Question 2- (-2,-5)

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3 years ago

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<u>Differentiate using the Quotient Rule</u> –

$\qquad$ $\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\$

According to the given question, we have –

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Let's solve it!

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2) \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\$

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$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\$

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2 years ago

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