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Westkost [7]
3 years ago
7

Which expressions are equivalent to 3 1/4 - (-5/8)

Mathematics
1 answer:
solniwko [45]3 years ago
6 0

3 1/4 + 5/8 is equivalent to 3 1/4 - (-5/8)

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andrew-mc [135]
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This is the answer
5 0
4 years ago
Read 2 more answers
44. Melissa helps her grandfather at his store. Each mornin
Goryan [66]

<h2>HOW TO: SOLVE AN APPLICATION</h2>

Step 1. Identify what you are asked to find and choose a variable to represent it.

Step 2. Write a sentence that gives the information to find it.

Step 3. Translate the sentence into an equation.

Step 4. Solve the equation using good algebra techniques.

Step 5. Check the answer in the problem and make sure it makes sense.

Step 6. Write a complete sentence that answers the question.

Remember that whatever the application, once we write the sentence with the given information (Step 2), we can translate it to a percent equation and then solve it.

Do you pay a tax when you shop in your city or state? In many parts of the United States, sales tax is added to the purchase price of an item. See Figure 6.7. The sales tax is determined by computing a percent of the purchase price.

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8 0
3 years ago
4. 1/37 of 111 + 1/3 of ? = 0<br> (1) 3 <br>2) 9 <br>3) 1 <br>4) can not be determined ​
lisov135 [29]

Answer:

4

Step-by-step explanation:

1/37 of 111+1/3 of 3= 4

1/37 of 111 +1/3 of 9=6

1/37 of 111 +1/3 of 1=3.3

7 0
2 years ago
A carpenter cuts a 2 metre length of wood into 6 pieces. What is the length of each piece? Give your answer to the nearest whole
irakobra [83]

assuming this means 6 equal lengths

 divide 2 meters by 6

2/6 =0.333 meters each

 0.333 meters = 333.33 mm

rounded off to nearest whole mm would be 333 mm's

4 0
3 years ago
Read 2 more answers
Pumping stations deliver oil at the rate modeled by the function D, given by d of t equals the quotient of 5 times t and the qua
goblinko [34]
<h2>Hello!</h2>

The answer is:  There is a total of 5.797 gallons pumped during the given period.

<h2>Why?</h2>

To solve this equation, we need to integrate the function at the given period (from t=0 to t=4)

The given function is:

D(t)=\frac{5t}{1+3t}

So, the integral will be:

\int\limits^4_0 {\frac{5t}{1+3t}} \ dx

So, integrating we have:

\int\limits^4_0 {\frac{5t}{1+3t}} \ dt=5\int\limits^4_0 {\frac{t}{1+3t}} \ dx

Performing a change of variable, we have:

1+t=u\\du=1+3t=3dt\\x=\frac{u-1}{3}

Then, substituting, we have:

\frac{5}{3}*\frac{1}{3}\int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du\\\\\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u}{u} -\frac{1}{u } \ du

\frac{5}{9} \int\limits^4_0 {(\frac{u}{u} -\frac{1}{u } )\ du=\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u } )

\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u })\ du=\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du

\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du=\frac{5}{9} (u-lnu)/[0,4]

Reverting the change of variable, we have:

\frac{5}{9} (u-lnu)/[0,4]=\frac{5}{9}((1+3t)-ln(1+3t))/[0,4]

Then, evaluating we have:

\frac{5}{9}((1+3t)-ln(1+3t))[0,4]=(\frac{5}{9}((1+3(4)-ln(1+3(4)))-(\frac{5}{9}((1+3(0)-ln(1+3(0)))=\frac{5}{9}(10.435)-\frac{5}{9}(1)=5.797

So, there is a total of 5.797 gallons pumped during the given period.

Have a nice day!

4 0
4 years ago
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