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Serjik [45]
3 years ago
10

Is 0.75 a solution for n < 1

Mathematics
1 answer:
attashe74 [19]3 years ago
7 0
Yes it could be one........
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The coordinates of the image of P(3,-4) under a reflection in the x-axis are:
lesantik [10]

Answer:

D. (-3,-4)

Step-by-step explanation:

PLACE YOUR GRAPH TOWARDS A MIRROR.....

8 0
2 years ago
The length of a rectangle is x feet. Its width is (x-7) feet. Draw and label a rectangle to represent this situation. Then write
a_sh-v [17]

Answer:

Perimeter of rectangle:

(4x - 14)\text{ feet}            

Step-by-step explanation:

We are given the following in the question:

Length of rectangle:

x\text{ feet}

Width of rectangle:

(x-7)\text{ feet}

Perimeter of rectangle:

2\times \text{(Length + Width)}

Expressions to calculate perimeter

1. ~2((x) + (x - 7))\text{ feet}\\2.~2(2x-7)\text{ feet}\\3.~ 4x-14\text{ feet}

The attached image shows the image of the rectangle.

3 0
3 years ago
(r-3)(r-1)<br> Help me please!!!
madreJ [45]

Answer:

= r²−4r+3

Step-by-step explanation:

(r - 3) (r - 1)

(r x r) + (r x -1) + (-3 x r) + (-3 x -1)

r² + - r - 3r + 3

= r²−4r+3

5 0
2 years ago
19. If the pg", and "terms of an A.P. are a,b, and c respectively. prove that: p(b-c) + (ca) + rſa-b) = 0 50 Approved by Curricu
professor190 [17]

Answer:

Step-by-step explanation:a = m + (p-1)*d

b = m + (q-1)*d

c = m + (r-1)*d

p(b-c) = p*(q-r)*d

q(c-a) = q*(r-p)*d

r(a-b) = r*(p-q)*d

p(b-c)+q(c-a)+r(a-b)

= p*(q-r)*d + q*(r-p)*d +r*(p-q)*d

= (pq-pr+qr-pq+rp-qr)*d

= 0*d = 0

So i prove p(b-c)+q(c-a)+r(a-b)=0 hope this is helpfull

4 0
3 years ago
Please help I don't undestand
Alla [95]

By applying the law of sines and some algebraic handling, the length of the side LJ is approximately equal to 3.517 units. (Right choice: D)

<h3>What is the missing side of the triangle according to the law of sines?</h3>

The law of sines presents a relationship between sides and <em>opposite</em> angles, which is described below:

9/sin 89° = LJ/sin 23°     (1)

LJ = 9 × sin 23°/sin 89°

LJ ≈ 3.517

By applying the law of sines and some algebraic handling, the length of the side LJ is approximately equal to 3.517 units. (Right choice: D)

To learn more on law of sines: brainly.com/question/21634338

#SPJ1

3 0
2 years ago
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