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dlinn [17]
3 years ago
10

2,023 nearest hundred

Mathematics
2 answers:
Tatiana [17]3 years ago
7 0
2,000 because 4 lower ignore it  5 or higher scoop it up

Oxana [17]3 years ago
4 0
2,000

hope this helps
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Consider the triangle below.
Pepsi [2]

The measure of angle P is 29 degrees

The sum of an interior angle of a triangle is 180 degrees. Given the following parameters:

  • m<M = 15x + 5
  • m<N = 3x + 2
  • m<P = 5x - 11

Taking the sum and equating to 180 degrees:

m<M + m<N + m<P = 180 degrees

15x + 5 + 3x + 2 + 5x - 11 = 180

23x - 4 = 180

23x = 184

x = 184/23

x = 8

Get the measure of m<P

m<P = 5x - 11

m<P = 5(8) - 11

m<P = 40 - 11

m<P = 29 degrees

Hence the measure of angle P is 29 degrees

Learn more on angles here: brainly.com/question/25770607

7 0
2 years ago
What is the approximate area of the shaded sector in the circle shown below?
BabaBlast [244]

Answer:

The sector given in the figure is a semi-circle because the degree measure of the chord is 180 degrees.

Area of semicircle = 0.5πr^{2} = 0.5π×4.5 = 6.75 sq. inches

4 0
3 years ago
Read 2 more answers
34 is added to x, the result is 98 . What is the value of x? Enter your answer in the box as a fraction in simplest form
KonstantinChe [14]

Not sure why it needs to be a fraction, if I am missing something please tell me. 64 or 64/1

4 0
3 years ago
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A triangle with vertices (0, 4), (3, 7) and (5, 1) is translated a distance of 4 units to the left. What are the new coordinates
STALIN [3.7K]
The new coords are (-4, 4), (-1,7) and (1,1)
5 0
3 years ago
Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
2 years ago
Read 2 more answers
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