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sertanlavr [38]
3 years ago
11

What would be the answer if this question? Solve: 8x/3x=16

Mathematics
1 answer:
Ulleksa [173]3 years ago
4 0

Answer:

8(60)/3(10) = 16  This is correct hope it helps

Step-by-step explanation:

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A delivery truck is transporting boxes of two sizes: large and small. The combined weight of the large box and a small box is 70
andre [41]

Answer:

3.45

Step-by-step explanation:

you have to do tihis then that

3 0
2 years ago
Compute the directional derivative of the function g(x,y)= sin(π(x−5y)).
e-lub [12.9K]

Answer:

Step-by-step explanation:

The directional derivative of a function in a particular direction u is given as the dot product of the unit vector in the direction of u and the gradient of the function

g(x,y) = sin(π(x−5y)

∇g = [(∂/∂x)î + (∂/∂y)j + (∂/∂z)ķ] [sin(π(x−5y))

(∂/∂x) g = (∂/∂x) sin (πx−5πy) = π [cos(π(x−5y))]

(∂/∂y) g = (∂/∂y) sin (πx−5πy) = - 5π [cos (π(x−5y))]

∇g = π [cos(π(x−5y))] î - 5π [cos (π(x−5y))] j

∇g = π [cos (π(x−5y))] [î - 5j]

So, the question requires a direction vector and a point to fully evaluate this directional derivative now.

8 0
3 years ago
Help! I can't seem to answer this. (question in photo)
german
The answer would be 48...

4 0
2 years ago
If 5 is subtracted from the square of a number ,the result is 4 , find the number.
Levart [38]

Answer:

9 I think

Step-by-step explanation:

I added 5 plus 4 to get 9 but I'm really not sure but I hope i helped!

7 0
3 years ago
-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




4 0
3 years ago
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