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3 years ago

Can someone please help me with this one question?

Mathematics

1 answer:

Scilla [17]3 years ago

8 0

It's been awhile since I've worked with infinite series and partial sums, but here are my thoughts:
A. the first 4 terms: -4, $- \frac{4}{3}$ , $-\frac{4}{9}$ , $- \frac{4}{27}$
B. In examining the partial sums of the series, it appears that the sequence produced has a limit and therefore the series would be convergent.
C. the limit or sum of the series looks to be -5 Below look at the sequence of partial sums:
-4, $-5 \frac{1}{3}$ , $-5 \frac{7}{9}$ , $-5 \frac{25}{27}$

So you can see we're getting closer and closer to -5

You might be interested in

Please help picture below

Gekata [30.6K]

A. The sculptor will have to sculpt away 1M on each side.

Explanation: 3 • 1_1/2 • 1_1/2
To get to 2 • 1/2 • 1/2, subtract 1 meter from each side of the rectangular prism and you’ll get that! :)

7 0

3 years ago

The brain volumes ?( cm cubed cm3?) of 20 brains have a mean of 1083.9 1083.9 cm cubed cm3 and a standard deviation of 122.2 122

Colt1911 [192]

Answer:

Range: (844.9,1333.7)

A brain volume of 1348.3 cm cubed can be considered significantly high.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1083.9 cm cubed

Standard Deviation, σ = 122.2 cm cubed

Range rule thumb:

This rule state that the the range of data is four times the standard deviation of the data.

$\text{Range} = 4\times \sigma = 4\times 122.2 = 488.8$

Upper Limit:

$\mu + 2\sigma = 1089.3 + 2(122.2) = 1333.7$

Lower limit:

$\mu - 2\sigma = 1089.3 - 2(122.2) = 844.9$

Since, 1348.3 does not lie in the range (844.9,1333.7), a brain volume of 1348.3 cm cubed can be considered significantly high.

6 0

3 years ago

7900 dollars is placed in an account with an annual interest rate of 5.5%. How much will be in the account after 11 years?

My name is Ann [436]

Answer:

$\$12,679.50$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=11\ years\\ P=\$7,900\\ A=?\\r=5.5\%=5.5/100=0.055$

substitute in the formula above

$A=7,900(1+0.055*11)$

$A=7,900(1.605)$

$A=\$12,679.50$

6 0

3 years ago

Solve for x: 5/x^2-4+2/x=2/x-2

IRINA_888 [86]

$\dfrac{5}{x^2 - 4} + \dfrac{2}{x} = \dfrac{2}{x - 2}$

$\dfrac{5}{(x + 2)(x - 2)} + \dfrac{2}{x} = \dfrac{2}{x - 2}$

$\dfrac{5}{(x + 2)(x - 2)} \times x(x + 2)(x - 2) + \dfrac{2}{x} \times x(x + 2)(x - 2) = \dfrac{2}{x - 2} \times x(x + 2)(x - 2)$

$5x + 2(x + 2)(x - 2) = 2x(x + 2)$

$5x + 2(x^2 - 4) = 2x^2 + 4x$

$5x + 2x^2 - 8 = 2x^2 + 4x$

$5x - 8 = 4x$

$x - 8 = 0$

$x = 8$

Now we look at the common denominator.

It is x(x + 2)(x - 2).

x cannot be zero, -2 or 2 because that would cause a zero in the denominator.

Since we get x = 8, and x = 8 does not have to be excluded from the domain, the answer is x = 8.

Answer: x = 8

6 0

3 years ago

Two vertical buildings 57 meters apart are 158 meters and 237 meters high. Find the angle of elevation from the top of the short

miskamm [114]

Given :

Two vertical buildings 57 meters apart are 158 meters and 237 meters high.

To Find :

The angle of elevation from the top of the shorter building to the top of the taller building.

Solution :

Distance between height of building, h = 237 - 158 = 79 m.

Distance between these building , d = 57 m.

Now,

$tan\ \theta = \dfrac{h}{d}\\\\tan\ \theta = \dfrac{79}{57}\\\\tan\ \theta = 1.386\\\\\theta = tan ^{-1} 1.386\\\\\theta = 54.19^{\circ}$

Therefore, the angle of elevation from the top of the shorter building to the top of the taller building is 54.19°.

Hence, this is the required solution.

4 0

3 years ago