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astraxan [27]
3 years ago
15

Can someone please help me with this one question?

Mathematics
1 answer:
Scilla [17]3 years ago
8 0
It's been awhile since I've worked with infinite series and partial sums, but here are my thoughts:
A. the first 4 terms:  -4, - \frac{4}{3}, -\frac{4}{9}, - \frac{4}{27}
B. In examining the partial sums of the series, it appears that the sequence produced has a limit and therefore the series would be convergent.
C. the limit or sum of the series looks to be -5    Below look at the sequence of partial sums:  
-4, -5 \frac{1}{3}, -5 \frac{7}{9}, -5 \frac{25}{27}

So you can see we're getting closer and closer to -5
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Answer:

0.0274

Step-by-step explanation:

The mean is \mu =114.8 and the standard deviation is \sigma =13.1.

Calculate

Z=\dfrac{X-\mu}{\sigma}

for X=140:

Z=\dfrac{140-114.8}{13.1}\approx 1.9237.

If X\sim N(114.8,\ 13.1), then Z\sim N(0,1)

and

Pr(X>140)=Pr(Z>1.9237).

Use table for normal distribution probabilities to get that

Pr(Z>1.9237)=1-Pr(Z\le 1.9237)=1-0.9726=0.0274.

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3 years ago
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Anna71 [15]

Answer:

11 yards

Step-by-step explanation:

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Given,

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Step-by-step explanation:

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