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astraxan [27]
4 years ago
15

Can someone please help me with this one question?

Mathematics
1 answer:
Scilla [17]4 years ago
8 0
It's been awhile since I've worked with infinite series and partial sums, but here are my thoughts:
A. the first 4 terms:  -4, - \frac{4}{3}, -\frac{4}{9}, - \frac{4}{27}
B. In examining the partial sums of the series, it appears that the sequence produced has a limit and therefore the series would be convergent.
C. the limit or sum of the series looks to be -5    Below look at the sequence of partial sums:  
-4, -5 \frac{1}{3}, -5 \frac{7}{9}, -5 \frac{25}{27}

So you can see we're getting closer and closer to -5
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Problem 1: Given the following probabilities P(Ac) = 0.45, P(B) = 0.34, and P(B|A) = 0.23. Find the following probabilities:
-BARSIC- [3]

Answer:

P(A)=0.55

P(A and B)=P(A∩B)=0.1265

P(A or B)=P(A∪B)=0.7635

P(A|B)=0.3721

Step-by-step explanation:

P(A')=0.45

P(A)=1-0.45=0.55

P(B∩A)=?

P(B|A)=0.23

P(B|A)=(P(A∩B))/P(A)

0.23=(P(A∩B))/0.55

P(A∩B)=0.23×0.55=0.1265

P(A∪B)=P(A)+P(B)-P(A∩B)

=0.55+0.34-0.1265

=0.7635

P(A|B)=[P(A∩B)]/P(B)=0.1265/0.34 ≈0.3721

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3 years ago
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Alfredo's painting his storage shed. He won't paint the top or bottom of the shed so he needs to calculate the lateral surface a
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Answer:

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