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kari74 [83]
3 years ago
7

7B1%7D%7Bb%7D" id="TexFormula1" title="make x the subject of formula in the equation 4a\sqrt{x} =\frac{1}{b}" alt="make x the subject of formula in the equation 4a\sqrt{x} =\frac{1}{b}" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
grigory [225]3 years ago
8 0

Step-by-step explanation:

4a\sqrt{x} = \frac{1}{b} \\\\\sqrt{x} = \frac{1}{4ab}\\\\x=  (\frac{1}{4ab})^{2} \\\\x= \frac{1}{16a^{2}b^{2}  }

kipiarov [429]3 years ago
3 0

Answer: x = (\frac{1}{4ab})^{2}

Step-by-step explanation:

Given:

4a\sqrt{x} = \frac{1}{b}

To make x the subject of the formula means that we want to make x to stand alone , the first thing to do is to multiply through by 1/4a , that is

\sqrt{x} = \frac{1}{4ab}

take the square  of both sides:

x = (\frac{1}{4ab})^{2}

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Answer:

Note: The full question is attached as picture below

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b) Test statistic = z

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= 0.12 / 0.043265

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Reject the null hypothesis.  There is sufficient evidence to support the researchers claim at the 1% significance level.

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Lynn gave her hair stylist a ​$5.10 tip. The tip was 17​% of the cost of the haircut. Write an equation to find​ b, the cost of
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iragen [17]

Answer:

The center of this circle is found at (4, -2) and the radius is 6.

Step-by-step explanation:

The equation for a circle in standard for is  ( x – h)² + ( y - k)² = r². In this equation, (h, k) is the center of the circle and r is the radius.

From the given equation, ( x – 4)² + ( y + 2)² = 36, h is already subtracted from x, so h = 4, but the k is not subtracted, so (y + 2) = [y - (-2)], and we see that k is -2. Therefore, the center of the circle is (4, -2) and 36 = r². By taking the square root of 36, we find that r = 6.

The center of this circle is found at (4, -2) and the radius is 6.

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