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2 years ago

7B1%7D%7Bb%7D" id="TexFormula1" title="make x the subject of formula in the equation 4a\sqrt{x} =\frac{1}{b}" alt="make x the subject of formula in the equation 4a\sqrt{x} =\frac{1}{b}" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

grigory [225]2 years ago

8 0

Step-by-step explanation:

$4a\sqrt{x} = \frac{1}{b} \\\\\sqrt{x} = \frac{1}{4ab}\\\\x= (\frac{1}{4ab})^{2} \\\\x= \frac{1}{16a^{2}b^{2} }$

kipiarov [429]2 years ago

3 0

Answer: $x = (\frac{1}{4ab})^{2}$

Step-by-step explanation:

Given:

$4a\sqrt{x} = \frac{1}{b}$

To make $x$ the subject of the formula means that we want to make $x$ to stand alone , the first thing to do is to multiply through by 1/4a , that is

$\sqrt{x} = \frac{1}{4ab}$

take the square of both sides:

$x = (\frac{1}{4ab})^{2}$

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May I please receive help

mafiozo [28]

Hello mate ☺️,

We know that m < 2 = 96°, as,

$m < 5 = 96°$ (Alternate angles are equal)

Now we know that m < 5 = 96°, so,

$→ m < 5 + m < 8 = 180°$ (Linear Pair angles are supplementary)

$→ 96° + m < 8 = 180°$

$→ m < 8 = (180 - 96)°$

$→ m < 8 = 84°$

Therefore, m<5 = 96° & m<8=84°

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2 years ago

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Dovator [93]

Bear with my working out lol,

8x3 = 24in^2
9x12 = 108in^2
6x7 = 42in^2
(11x4) / 2 = 22in^2

Total = 196in^2

Try that, I couldn’t tell where the tip on the triangle fell at. So it could be wrong but that is what I got and what I would put :)

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2 years ago

Read 2 more answers

A stock has a price of $58.63. This is $5.92 less than the price of the stock yesterday. Write and solve an equation to find the

inysia [295]

Answer: $52.71

Step-by-step explanation:

Today's price= $58.63

Yesterday's price= y

Difference= $5.92

y+5.92 = 58.63

y = 58.63 - 5.92

= $52.71

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2 years ago

How do i solve this?

vazorg [7]

Usually I would use my head, but you can use whatever you want.

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2 years ago

The number of events is 29, the number of trials is 298, the claimed population proportion is 0.10, and the significance leve

Nina [5.8K]

Answer:

$z=\frac{0.0973 -0.1}{\sqrt{\frac{0.1(1-0.1)}{298}}}=-0.155$

$p_v =2*P(Z$

And we can use excel to find the p value like this: "=2*NORM.DIST(-0.155;0;1;TRUE)"

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly different from 0.1 .

Step-by-step explanation:

1) Data given and notation

n=298 represent the random sample taken

X=29 represent the events claimed

$\hat p=\frac{29}{298}=0.0973$ estimated proportion

$p_o=0.1$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is 0.1 or no.:

Null hypothesis: $p=0.1$

Alternative hypothesis: $p \neq 0.1$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.0973 -0.1}{\sqrt{\frac{0.1(1-0.1)}{298}}}=-0.155$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(Z$

And we can use excel to find the p value like this: "=2*NORM.DIST(-0.155;0;1;TRUE)"

We can do the test also in R with the following code:

> prop.test(29,298,p=0.1,alternative = c("two.sided"),conf.level = 1-0.05,correct = FALSE)

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3 years ago