Help I’m stuck in algebra 2

Find the range of the given data set. -4, -3, -1, -1, 0, 1

Dovator [93]

Answer:

5

Step-by-step explanation:

To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest value in the set.

7 0

3 years ago

For fun question

ZanzabumX [31]

Consider the function $f(x)=x^{1/3}$ , which has derivative $f'(x)=\dfrac13x^{-2/3}$ .

The linear approximation of $f(x)$ for some value $x$ within a neighborhood of $x=c$ is given by

$f(x)\approx f'(c)(x-c)+f(c)$

Let $c=64$ . Then $(63.97)^{1/3}$ can be estimated to be

$f(63.97)\approxf'(64)(63.97-64)+f(64)$
$\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375$

Since $f'(x)>0$ for $x>0$ , it follows that $f(x)$ must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function $f(x)$ . This means the estimated value is an overestimation.

Indeed, the actual value is closer to the number 3.999374902...

4 0

3 years ago

Rewrite each of the following terms as an extended product. Consider carefully your order of operations and remember that expone

sergey [27]

The detailed explanation of the question is provided in the attached image.

Hope this helps :)

8 0

2 years ago

Read 2 more answers

What is 48% 0f 60,000000

Tanzania [10]

That'd be : 28.8 . I hope this helps. This is it step by step.

60/x=100/48
(60/x)*x=(100/48)*x 
60=2.08333333333*x
(2.08333333333) to get x
60/2.08333333333=x 
28.8=x 
x=28.8

5 0

2 years ago

A researcher records the amount of time (in minutes) that parent child pairs spend on social networking sites to test whether th

ki77a [65]

Answer:

(a) A matched pair design is used to perform the test.

(b) Each sample is of size 30.

(c) The null hypothesis is rejected.

(d) The effect size of the test is medium.

Step-by-step explanation:

A statistical experiment is performed to determine whether the amount of time (in minutes) that parent-child pairs spend on social networking sites to test show any generational differences.

Given:

MD = -42 minutes

t₍₂₉₎ = 4.021

p < 0.05

d = 0.49

The hypothesis is:

H₀: There is no difference between the means, i.e. μ₁ = μ₂.

Hₐ: There is a significant difference between the means, i.e. μ₁ ≠ μ₂.

(a)

A matched pair design is used to perform the test.

In a matched pair design the participant of the two groups are related in some way. For example, the same sample is tested before and after applying the treatment.

In this case the matched are pairs are of children and their parents. And the treatment is the amount of time spent on social networking sites.

(b)

The degrees of freedom of a matched pair design is:

df = n - 1

29 = n - 1

n = 29 + 1

n = 30

Thus, each sample is of size 30.

(c)

The p-value of the test statistic is < 0.05.

If the p-value is less than the significance level α (say, 0.05) then the null hypothesis is rejected and vise-versa.

Since p < 0.05 the null hypothesis is rejected concluding that there is a significant difference between the amount of time spent on social networking sites by parents and children.

(d)

The estimated value of Cohen's d is, d = 0.49.

A Cohen's d value between the range 0.50 to 0.80 is considered as medium.

Thus, the effect size of the test is medium.

3 0

3 years ago