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3 years ago

How do you simplify 12/28

Mathematics

2 answers:

vodka [1.7K]3 years ago

6 0

You have to divide both numbers equally, so I divided 12 and 28 by 4, I got 3/7

uranmaximum [27]3 years ago

5 0

12/28 can be simplified by dividing both numerator and denominator by 4
3/7

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alex has twice as much money as jennifer. jennifer has $6 less than shannon. Together they have 54$. How much money does each ha

aleksley [76]

54-6 = 48

48/4 (Alex-twice, Jennifer, Shannon)
48/4= 12

Alex- 12 x 2 = $24

Jennifer- 12 = $12

Shannon- 12+6 (the 6 I subtracted 54-6) = $18

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3 years ago

What is 6/5 divided by 4/3

Anna007 [38]

Answer:

9/10

Step-by-step explanation:

5 0

3 years ago

A test consists of 10 true or false questions. To pass the test a student must answer at least eight questions correctly. If the

forsale [732]

<h3>The probability of student passing the quiz with at least 50% of the questions correct is 0.05457.</h3>

Step-by-step explanation:

Here, the total number of T/F question = 10

The minimum answers needed correctly answered = 8

So, student needs to answer at least 8 questions correctly.

Here, the possibility of answering a question correctly = $(\frac{1}{2})$ = p = 0.5

Also, the possibility of answering a question wrong = $(\frac{1}{2})$ = q = 0.5

Now, to pass he needs to answer 8 or more ( 8 , 9 or 10) answers correctly.

P(answering 8 correct answer) = $^{10}C_8(p)^8(q)^2 = ^{10}C_8(0.5)^8(0.5)^2 = 0.0439$

P(answering 9 correct answer) = $^{10}C_9(p)^9(q)^1 = ^{10}C_9(0.5)^9(0.5)^1 = 0.0097$

P(answering 10 correct answer) = $^{10}C_{10}(p)^{10}(q)^0 = ^{10}C_{10}(0.5)^{10}(0.5)^0 = 0.00097$

So, the total Probability = P(8) + P(9) + P(10)

= (0.0439) + (0.0097) + (0.00097)

= 0.05457

Hence, the probability that the student passes the quiz with at least 8 of the questions correct is 0.05457.

6 0

3 years ago

Can someone pls help me? I’m confused!

OleMash [197]

Answer:

? = 24

Step-by-step explanation:

Pizzas = 3

Because of this, burgers must be 2

2³ = 8

Tacos = 8

8 + 8 + 8 = 24

7 0

3 years ago

Read 2 more answers

Which of the following geometric series converges?

Artist 52 [7]

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term a and common ratio |r| < 1. Then the n-th partial sum (the sum of the first n terms) of the sequence is

$S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}$

Multiply both sides by r :

$rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n$

Subtract the latter sum from the first, which eliminates all but the first and last terms:

$S_n-rS_n=a-ar^n$

Solve for $S_n$ :

$(1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}$

Then as gets arbitrarily large, the term $r^n$ will converge to 0, leaving us with

$S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}$

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

(II) -1.1/(1 + 1/10) = -1

(III) 27/(1 + 1/3) = 18

8 0

3 years ago