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Yuri [45]
3 years ago
8

I don't know how to answer number 9 and 10. Can someone please help me?

Mathematics
1 answer:
kogti [31]3 years ago
5 0

AB = AC = 32

SR = TR = 7

Solution:

Question 9:

<u>Tangent theorem of a circle:</u>

Lengths of tangents drawn from an same external point to a circle are equal.

In figure AB and AC are tangents drawn from same an external point A.

By tangent theorem of a circle,

⇒ AB = AC

\Rightarrow 2x^2=8x

Divide both side of the equation by x.

$\Rightarrow \frac{2x^2}{x} =\frac{8x}{x}

$\Rightarrow 2x =8

Divide by 2 on both side of the equation.

$\Rightarrow \frac{2x}{2} =\frac{8}{2}

$\Rightarrow x =4

Substitute x = 4 in AB and AC.

AB=2(4)^2=32

AC=8(4)=32

Question 10:

By tangent theorem of a circle,

⇒ SR = TR

$\Rightarrow y=\frac{y^2}{7}

Multiply by 7 on both side of the equation, we get

$\Rightarrow 7y =y^2

Divide by y on both side of the equation, we get

$\Rightarrow 7 =y

Substitute y = 7 in SR and TR

SR=y=7

$TR=\frac{7^2}{7} =7

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