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Ksivusya [100]
4 years ago
13

58.14 rounded to the nearest tenth

Mathematics
2 answers:
kakasveta [241]4 years ago
8 0
58.1 since 4 is not greater than 5 so it cant be rounder up to 2
Akimi4 [234]4 years ago
3 0
58.1 would be the answer I believe
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Let B1W2 denote the outcome that the first ball drawn is B1 and the second ball drawn is W2. Because the first ball is replaced
Sati [7]

Answer:

\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\

W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}

Step-by-step explanation:

\text{If an urn contains two blue balls} (denoted \:B_1 \:and \:B_2) \text{and three white balls},(denoted \:W_1, W_2, \:and\: W_3)

If One ball is drawn, its color is recorded, and it is replaced in the urn. Then another ball is drawn and  its color is recorded.

The 25 Possible outcomes of this experiment are listed below:

\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\

W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}

The tree diagram of this event is also attached.

6 0
4 years ago
10. The product of -2 and a number n is increased by 15. The result is greater than 3. Choose the inequality that represents the
natita [175]

Answer:

-2n+15>3

Step-by-step explanation:

6 0
1 year ago
Dina took 12 hours to read a 600 page book What was her page per minute rate?
jok3333 [9.3K]

50 divide to find the answer

4 0
3 years ago
A whole number has a 6 in the hundreds place, and all of its other digits are zero. If the 6 is moved from the hundreds place to
DaniilM [7]

Answer:

The original number is 10 times the new number.

Step-by-step explanation:

5 0
3 years ago
Two dice are thrown simultaneously. Given that sum of the numbers is NOT more than 5, what is the probability that sum is more t
defon
A method to know the probability is to list down all of the possible combinations that would present an outcome of not more than 5. This is listed below:

1 + 4
4 + 1
2 + 3
3 + 2
1 + 1
2 + 2
1 + 2
2 + 1
1 + 3
3 + 1

There are 10 possible outcomes. But among these, the only ones that can have a sum more than 3 are:

1 + 4
4 + 1
2 + 3
<span>3 + 2
</span>2 <span>+ 2
</span>1 + 3
3 + 1

There are only 7 possible outcomes that meet both requirements. Given that there are 7 outcomes within the total of 10, the probability would be 7/10, or 0.7.

3 0
3 years ago
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