Answer:
slope is 
Step-by-step explanation:
1,-1 -3,2 are two points on the graph
the equation to find slope is 
so 
or you can count how many places it changed in the equation 
Yes because all equilateral triangles have equal angles and side lengths so they are all similar. hope i helped -J
we know that
For a spherical planet of radius r, the volume V and the surface area SA is equal to

The
ratio of these two quantities may be written as

we know


therefore
the answer is

Yo sup??
the answer is 1 because
P(E)+P(E')=1
where E is the event and
E' is the complement of the event
Hope this helps