Answer:
-6
Step-by-step explanation:
-6/b-50=-49
step1;collect like terms
-6/b=-49+50
-6/b=1
step2;cross multiply
-6/b=1
-6=1b(1b can also be regarded as b)
b=-6
47. You subtract the lowest number from the highest to get your range.
Answer:
absolute max is 120 and absolute min is -8
Step-by-step explanation:
Find critical numbers
f'(x) = 3x^2 - 12x + 9 = 0
= 3(x^2 - 4x + 3) = 0
3(x-3)(x-1) = 0
(x-3) = 0 or (x-1)=0
x = 1,3
Test them!
x<1 Sign of f' on this interval is positive
1<x<3 Sign of f' on this interval is negative
x>3 Sign of f' on this interval is positive
f(x) changes from positive to negative at x = 1 which means there is a relative maximum here.
f(x) changes from negative to positive at x = 3 which means there is a relative minimum here.
Test the endpoints to find the absolute max and min.
f(-1) = -8
f(1) = 12
f(3) = 8
f(7) = 120
The absolute maximum value of f is 120 and the absolute minimum value of f is -8.
Answer:
i think 30
Step-by-step explanation:
the best choice
The answer is <span>6x+7x=26
</span>
I got this by dividing 26/2=13 then I subtracted 13-1=12 then divide 12/2=6
Then I had the first part, 6x+__=26 where x = 2
I still have 14 left, so I divided that by 2 (7) and I had the full equation.
6x+7x=26
Hope this helped! Please comment or DM me if you have anymore questions or don't understand :)
