All categories

3 years ago

PLEASE HELP ASAP!

2 answers:

6 0

Ok so I will take this from the top, lets start out with choice A (-1,-12) we will need to see if the answer is equal to A. so first lets just merge these two problems into eachother to get 4x-8=2x-10 now, after subtracting 2x from each side we get 2x-8=-10. Now, add 8 to both sides which will give us 2x=-2... now it is simple, just divide -2 by 2 to get an answer for x as -1...Answer A is the correct answer

Naddika [18.5K]3 years ago

5 0

$\begin{cases}y=2x-10\\y=4x-8\end{cases}\\\\\\
4x-8=2x-10\\\\4x-2x=-10+8\\\\2x=-2\qquad|:2\\\\\boxed{x=-1}\\\\\\y=2x-10\\\\y=2\cdot(-1)-10\\\\y=-2-10\\\\\boxed{y=-12}\\\\\\\begin{cases}x=-1\\y=-12\end{cases}\\\\\\$

Answer A)

You might be interested in

19 points please hurry

Readme [11.4K]

Answer:

i think the answer is b give me brainliest please

Step-by-step explanation:

5 0

3 years ago

+50 point quiz:

solmaris [256]

Answer:

125 dollars will get

sk sk ta N me an

5 0

2 years ago

Read 2 more answers

Please help . I will mark brainliest

Step2247 [10]

Answer:

c: car b was 10 miles east of car a

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t

andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ. $e^{-\lambda.x}$

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - $e^{-\lambda.x}$

(a) Probability of distance at most 100m, with λ = 0.0143:

F(100) = 1 - $e^{-0.0143.100}$

F(100) = 0.76

Probability of distance at most 200:

F(200) = 1 - $e^{-0.0143.200}$

F(200) = 0.94

Probability of distance between 100 and 200:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = $\frac{1}{\lambda}$

E(X) = $\frac{1}{0.0143}$

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = $\sqrt{\frac{1}{\lambda^{2}} }$

σ = $\sqrt{\frac{1}{0.0143^{2}} }$

σ = 69.93

Distance exceeds the mean distance by more than 2σ:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - $e^{-0.0143*209.79}$ )

P(X > 209.79) = 0.0503

P(X≤m) = 0.5

$\int\limits^m_0 f({x}) \, dx$ = 0.5

$\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx$ = 0.5

$\lambda.\frac{e^{-\lambda.x}}{-\lambda}$ = $-e^{-\lambda.x} + e^{0}$

$1 - e^{-\lambda.m}$ = 0.5

$-e^{-\lambda.m}$ = - 0.5

ln( $e^{-0.0143.m}$ ) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

6 0

3 years ago

Find inequality represented by graph please help

kirill115 [55]

U have a dashed line...meaning there is no equal sign in the problem.....it goes thru the origin (0,0)...meaning the y int is 0....u have a slope of 3/4

so ur inequality is : y = 3/4x <==

5 0

3 years ago