Box one ratios
Box two 35:2= 70:4
Rewrite so
x
is on the left side of the inequality.
12
+
8
x
−
3
x
≥
5
+
2
x
−
2
Subtract
3
x
from
8
x
.
12
+
5
x
≥
5
+
2
x
−
2
Subtract
2
from
5
.
12
+
5
x
≥
2
x
+
3
Move all terms containing
x
to the left side of the inequality.
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12
+
3
x
≥
3
Move all terms not containing
x
to the right side of the inequality.
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3
x
≥
−
9
Divide each term by
3
and simplify.
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x
≥
−
3
The result can be shown in multiple forms.
Inequality Form:
x
≥
−
3
Interval Notation:
[
−
3
,
∞
)
Answer:
<u><em>Good luck!
</em></u>
<u><em></em></u>
0..
Let Sarah's age be s and Antonio's age be a.
According to your question,
2a + 3s = 34
s = 5a
substituting the value of s in eq. 1,
2a + 3(5a) = 34
= 2a + 15 a = 34
17a = 34
thus, a = 34/17 = 2
substituting the value of a is s,
s = 5(2)
= 10
Thus, Sarah's age is 10 years and Antonio's age is 2 years.
Answer:
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