The area of a circle is <u>(pi) x (the circle's radius)</u>²
The circle's radius is (1/2) of (its diameter).
Area = (pi) x (12/2 inches)² =
(pi) x (6 inches)² =
(3.14) x (36 square inches) = <em>113 square inches</em> (rounded)
Hello,
To solve, factour out the expression: <span>9a^4b^4-27a^3b^3+18a^3b^2.
Once factoured out you get the GCF 9a^(3)b^(2)
Faith xoxo</span>
For an even function f(x) = f(-x)
So its option A
Solve the following system by Elimination:
{7 x + 3 y = 22 | (equation 1)
{4 y = 20 | (equation 2)
Divide equation 2 by 4:
{7 x + 3 y = 22 | (equation 1)
{0 x+y = 5 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{7 x+0 y = 7 | (equation 1)
{0 x+y = 5 | (equation 2)
Divide equation 1 by 7:
{x+0 y = 1 | (equation 1)
{0 x+y = 5 | (equation 2)
Collect results:
Answer: {x = 1, y = 5
_____________________________________________________
Solve the following system:
{y - 2 x = 10 | (equation 1)
{4 x - y = -14 | (equation 2)
Swap equation 1 with equation 2:
{4 x - y = -14 | (equation 1)
{-(2 x) + y = 10 | (equation 2)
Add 1/2 × (equation 1) to equation 2:
{4 x - y = -14 | (equation 1)
{0 x+y/2 = 3 | (equation 2)
Multiply equation 2 by 2:
{4 x - y = -14 | (equation 1)
{0 x+y = 6 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = -8 | (equation 1)
{0 x+y = 6 | (equation 2)
Divide equation 1 by 4:
{x+0 y = -2 | (equation 1)
{0 x+y = 6 | (equation 2)
Collect results:
Answer: {x = -2, y = 6
