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dusya [7]
3 years ago
8

Amir has $200 budget to spend on a graduation party for his son he already has purchased $122 worth of drinks and party supplies

he wishes to buy chicken pizza or subs for the main course prices including tax are shown below

Mathematics
1 answer:
Bas_tet [7]3 years ago
5 0

Answer: C, D, and E

Step-by-step explanation:

200-122=78 remaining

A: 7*11.75= 82.25

B: 10*11.75= 117.50

C: 9*6.80=61.20

D: 11*6.80=74.80

E: 70*1.10=77.00

F: 71*1.10=78.10

Only C, D and E are below the dollars remaining in the budget.

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Answer:

1. 570

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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
A group of 15 people are going to run a race. The top 8 will advance to the finals. Determine if the situation is a permutation
LUCKY_DIMON [66]

For the given situation we have a total of 259,459,200 permutations.

<h3>How many permutations are?</h3>

First, how we know that it is a permutation?

Because the order matters, we aren't only selecting 8 out of the 15 people, but these 8 selected also have an order (is not the same thing to finish the race first than fourth, for example).

Then we need to find the number of permutations, to do it, we need to find the numbers of options for each of the 8 positions.

  • For the first position there are 15 options.
  • For the second position ther are 14 options (one runner already finished).
  • For the third position there are 13 options.
  • And so on.

Then the total number of permutations (product between the numbers of options) is:

P = 15*14*13*12*11*10*9*8 = 259,459,200

If you want to learn more about permutations:

brainly.com/question/11732255

#SPJ1

8 0
3 years ago
Slope 1/2 = goes through (2, 6) ​
Mekhanik [1.2K]
Y = 1/2x+5 I think that’s it
7 0
3 years ago
How much wrapping is needed for a package that is shaped like a cube<br> 16 in. on each edge?
PtichkaEL [24]

Answer:

1536 in^2

Step-by-step explanation:

This is basically asking for the surface area so knowing that is a cube all the sides are equal so one side would be 16(16) which is 256 in ^2.  The knowing that there is 6 sides you would multiply it by 6 which is 256(6)= 1536^2

3 0
3 years ago
Solve the initial value problem where y′′+4y′−21 y=0, y(1)=1, y′(1)=0 . Use t as the independent variable.
igor_vitrenko [27]

Answer:

y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}

Step-by-step explanation:

y′′ + 4y′ − 21y = 0

The auxiliary equation is given by

m² + 4m - 21 = 0

We solve this using the quadratic formula. So

m = \frac{-4 +/- \sqrt{4^{2} - 4 X 1 X (-21))} }{2 X 1}\\ = \frac{-4 +/- \sqrt{16 + 84} }{2}\\= \frac{-4 +/- \sqrt{100} }{2}\\= \frac{-4 +/- 10 }{2}\\= -2 +/- 5\\= -2 + 5 or -2 -5\\= 3 or -7

So, the solution of the equation is

y = Ae^{m_{1} t} + Be^{m_{2} t}

where m₁ = 3 and m₂ = -7.

So,

y = Ae^{3t} + Be^{-7t}

Also,

y' = 3Ae^{3t} - 7e^{-7t}

Since y(1) = 1 and y'(1) = 0, we substitute them into the equations above. So,

y(1) = Ae^{3X1} + Be^{-7X1}\\1 = Ae^{3} + Be^{-7}\\Ae^{3} + Be^{-7} = 1      (1)

y'(1) = 3Ae^{3X1} - 7Be^{-7X1}\\0 = 3Ae^{3} - 7Be^{-7}\\3Ae^{3} - 7Be^{-7} = 0 \\3Ae^{3} = 7Be^{-7}\\A = \frac{7}{3} Be^{-10}

Substituting A into (1) above, we have

\frac{7}{3}B e^{-10}e^{3} + Be^{-7} = 1      \\\frac{7}{3}B e^{-7} + Be^{-7} = 1\\\frac{10}{3}B e^{-7} = 1\\B = \frac{3}{10} e^{7}

Substituting B into A, we have

A = \frac{7}{3} \frac{3}{10} e^{7}e^{-10}\\A = \frac{7}{10} e^{-3}

Substituting A and B into y, we have

y = Ae^{3t} + Be^{-7t}\\y = \frac{7}{10} e^{-3}e^{3t} + \frac{3}{10} e^{7}e^{-7t}\\y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}

So the solution to the differential equation is

y = \frac{7}{10} e^{3(t - 1)} + \frac{3}{10}e^{-7(t - 1)}

6 0
4 years ago
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