The maximum radius of each ball is 3.33 cm.
<h3>What is a Cylinder?</h3>
A cylinder is a three-dimensional figure which is made of two parallel circular bases separated at a certain distance by a curved surface of the same radius as that of the bases.
A 20 cm nail perfectly fits the cylinder.
So the height of the cylinder = 20cm.
A sphere is a three-dimensional geometrical figure analogous to a circle. All the points of the sphere are at the same distance from the center.
If 3 spheres have to be fitted inside the cylinder,
The sum of the diameter of the spheres will be equal to the height of the cylinder.
The spherical balls are identical and so will have the same diameter
Let the maximum diameter of the sphere that can fit in the cylinder is d cm
Then,
d + d + d = 20
3d = 20
d = 20/3 = 6.67 cm
r = 3.33 cm
The maximum radius that the spheres can have to fit in the cylinder is 3.33 cm.
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Answer:
50
Step-by-step explanation:
^^^^^^^^^ (please give me brainliest)
Answer:
x=28°
y=152°
Step-by-step explanation:
x=28°
y=152°
Asked and answered elsewhere.
brainly.com/question/9247314You obviously don't mind using "technology" (Brainly) to answer these questions. A graphing calculator can do quadratic regression on the sequence and tell you its formula.
If you want to do it by hand, you can write the equation
.. y = ax^2 +bx +c
and substitute three of the given points. Then solve the resulting three linear equations for a, b, and c.
.. 4 = a +b +c
.. 7 = 4a +2b +c
.. 12 = 9a +3b +c
Subtracting the first equation from the other two reduces this to
.. 3 = 3a +b
.. 8 = 8a +2b
The latter can be divided by 2, so reduces to
.. 4 = 4a +b
Subtracting the first of the reduced equations from this, you have
.. 1 = a
so
.. 3 = 3*1 +b
.. 0 = b
and
.. 4 = a + b + c = 1 + 0 + c
.. 3 = c
And your equation is
.. y = x^2 +3 . . . . . . as shown previously
Hello :
the normal vector of the plane is : d' = [4,-1,5]...(vector perpendicular to the plane)<span>
d </span><span>⊥ d' because : (4)(2)+(-1)(3)+(5)(1)=0
</span>the line is perpendicular to the plane .