Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Answer:
x=27
Step-by-step explanation:
(2x-18)+(4x)=180 bc its a straight line
simplify
6x-18=180
-18 -18
6x=162
divide
x=27
Change each of the fractions into decimals.
1/8 becomes 0.125
-1/7 becomes -0.143
and -0.02555
0.2
In order from least to greatest,
-0.143, -0.02555, 0.125, 0.2
OR
-1/7, -0.02555, 1/8 and 0.2
1. x = -4 ; f(x) = -(-4) = 4
2. x = -3 ; f(x) = 2(-3) + 1 = -5
3. x = 0 ; f(x) = 2(0) + 1 = 1
4. x = 2 ; f(x) = 2 + 3 = 5
5. x = 5 ; f(x) = 5 + 3 = 8
Answer:I think it’s 61 minutes
Step-by-step explanation: