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MatroZZZ [7]
4 years ago
9

MCHS sold 150 tickets at the last basketball game. Student tickets cost $3 and adult tickets cost $5. If they sold $580 worth of

tickets, how many of each type of ticket did they sell?
Mathematics
1 answer:
Tanya [424]3 years ago
7 0

Answer:the number of student tickets that were sold is 85

the number of adult tickets that were sold is 65

Step-by-step explanation:

Let x represent the number of student tickets that were sold.

Let represent the number of adult tickets that were sold.

MCHS sold 150 tickets at the last basketball game. This means that

x + y = 150

Student tickets cost $3 and adult tickets cost $5. If they sold $580 worth of tickets, it means that

3x + 5y = 580 - - - - - - - - - - -1

Substituting x = 150 - y into equation 1, it becomes

3(150 - y) + 5y = 580

450 - 3y + 5y = 580

- 3y + 5y = 580 - 450

2y = 130

y = 130/2 = 65

Substituting y = 65 into x = 150 - y, it becomes

x = 150 - 65 = 85

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Vikentia [17]

To solve this, follow these steps:

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Distribute the 9 within the parenthesis:

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Then combine like terms:

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These two then cancel each other out completely.

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Hope this helps!

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3 years ago
Choose the best estimate for the multiplication problem below. 74 X 61
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Read 2 more answers
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4 0
3 years ago
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