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Ronch [10]
3 years ago
15

What is the value of the y-intercept of the line 2x+5y=12?

Mathematics
2 answers:
Paladinen [302]3 years ago
8 0

Using the slope-intercept form, the slope is  

2 /5  2/5.M= 25

madreJ [45]3 years ago
7 0

Answer:

y=-2/5x+2 2/5

Step-by-step explanation:

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1<br> 3<br> 4<br> 0.5<br> - 3<br> - 6.5<br> - 10<br> What is the linear function?
Wewaii [24]

Answer: it’s probably negative 6.5 but there has to be a grid to be more clear

Step-by-step explanation:

7 0
3 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
3 years ago
Jonas wants to mail a package that weighs 4.2 kilogram. how much dose the package weigh in pounds?
mash [69]

jonas wants to mail a package that weighs 4.2 kilogram. how much dose the package weigh in pounds?​

we know that

1 kg = 2.20462262185 lb

1 kg=2.2 lb

we have

4.2 kg

Convert to pounds

so

4.2 kg=4.2*(2.2)=9.24 pounds

therefore

the answer is 9.24 pounds

7 0
1 year ago
At a point on the ground 35 ft from the base of a tree, the distance to the top of the tree is 1 ft more than 3 times the height
jolli1 [7]

Answer:

Step-by-step explanation:

This is a question that uses the Pythagorean Theorem.

a = 35 feet

b = x            which is the height of the tree.

c = 3*x + 1   so we are trying to find x.  Substitute into a b and c

a^2 + b^2 = c^2

35^2 + x^2 = (3x + 1)^2        

35^2 + x^2 = 9x^2 + 6x + 1     Subtract x^2 from both sides.

35^2 = 8x^2 + 6x + 1               Subtract 35^2 from both sides.

0 = 8x^2 + 6x + 1 - 35^2

0 = 8x^2 + 6x - 1224

Does this factor?

(x + 12.75)(x - 12)

x - 12 = 0 is the only value that works.

x = 12

The tree is 12 feet high.

Note: I used the quadratic formula to solve this.

6 0
3 years ago
Read 2 more answers
Equipment was purchased for $85,000 on january 1, 2015. freight charges amounted to $3,500 and there was a cost of $10,000 for b
Elena-2011 [213]
85000+3500+10000=98500 is a historic price of equipment. Annual depreciation is (98500-15000)/5=83500/5=16700. At december 31 2016 will be gone 2 years-2015 and 2016. So the accumulated depreciation will be 2*16700=33400
3 0
3 years ago
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