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lara [203]
2 years ago
12

Adam and Brianna plan to install a new tile floor in a classroom. Adam works at a constant rate of 50 tiles per hour, and Briann

a works at a constant rate of 55 tiles per hour. If the new floor consists of exactly 1400 tiles, how long will it take Adam and Brianna working together to complete the classroom floor?
Mathematics
1 answer:
natima [27]2 years ago
7 0

Answer:

t≅13.33h

Step-by-step explanation:

Adam (A) works at constant rate of 50tiles/h

Briana (B) works at constant rate of 55tiles/h, this means that A=50 tiles per hour and B=55 tiles per hour, then A+B = 105tiles/h together, but the floor consists of 1400tiles, so if 105 tiles are installed in one hour, then 1400 tiles in how long they will be installed?

t = 1400tiles*h/105tiles≅ 13.33 h

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The area of the walkway is 168 square feet if Ms. Rich is creating a walkway around her rectangular garden. If the walkway will be 3 feet wide, and the garden is 10ft by 12ft.

<h3>What is the area of the rectangle?</h3>

It is defined as the space occupied by the rectangle, which is planner 2-dimensional geometry.

The formula for finding the area of a rectangle is given by:

Area of rectangle = length × width

The dimensions of the garden = 10 ft by 12 ft

Area = 10×12 = 120 square feet

The width of the walkway = 3 feet

If we create a walkway around the garden, it will be a rectangle around the garden.

So the dimensions for the bigger rectangle = (3+10+3) ft by (3+12+3) ft

Area of the bigger rectangle = 16×18 = 288 square feet

So the area of the walkway = 288 - 120 = 168 square feet

Thus, the area of the walkway is 168 square feet if Ms. Rich is creating a walkway around her rectangular garden. If the walkway will be 3 feet wide, and the garden is 10ft by 12ft.

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4 0
1 year ago
The length of a rectangle is 5 more than twice the width. the perimeter is 130. what is the area?
vekshin1
<span>L the length     W the width 

The length of a rectangle is 5 more than twice the width</span>
L = 5+ 2W

<span>the perimeter is equal the sum of sides =130
</span>
L+L+W+W =130

by subtitution we replace L by <span>L = 5+ 2W

</span>5+ 2W+<span>5+ 2W +W+W = 130
</span>
6W= 120

w= 20              <span>L = 5+ 2W= 5+ 40=45</span>
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