Question

Write an inequality for x that would give this isosceles triangle and perimeter of at least 137 ft. 4x+3 2x+7

Answer 1

Answer:

The inequality is $8x+17\geq 137$

Step-by-step explanation:

Given : The isosceles triangle with base and side 4x+3, 2x+7.

And the perimeter is at least 137ft.

To write : An inequality for x

Solution : Let the base $b=4x+3$ and sides $s=2x+7$

The perimeter of Isosceles triangle is $P=2s+b$

where s=side and b=base

Now, we have given that perimeter is at least 137 ft.

Therefore, the inequality form is

$2(2x+7)+(4x+3)\geq 137$

$4x+14+4x+3\geq 137$

$8x+17\geq 137$