The distance between the goals on a soccer field is 52 meters. Each goal has a box that extends 5.49 meters into the field.What
is the distance from the front of the box at one end of the field to the front of the box at the other end of the field?
How can I show my work?
How can I show my work?
1 answer:
Answer:
41.02 meters.
Step-by-step explanation:
See the attached diagram.
The distance between the goals of a soccer field is 52 meters. Each goal has a box that extends 5.49 meters into the field.
If the distance from the front of the box at one end of the field to the front of the box at the other end of the field is x meters, then we can write the equation as
5.49 + x + 5.49 = 52
⇒ x + 10.98 = 52
⇒ x = 41.02 meters. (Answer)
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Which begins at zero.
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just as the parent function
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Answer: The hook would be 2.2 inches (approximately) above the top of the frame
Step-by-step explanation: Please refer to the picture attached for further details.
The top of the picture frame has been given as 9 inches and a 10 inch ribbon has been attached in order to hang it on a wall. The ribbon at the point of being hung up would be divided into 5 inches on either side (as shown in the picture). The line from the tip/hook down to the frame would divide the length of the frame into two equal lengths, that is 4.5 inches on either side of the hook. This would effectively give us two similar right angled triangles with sides 5 inches, 4.5 inches and a third side yet unknown. That third side is the distance from the hook to the top of the frame. The distance is calculated by using the Pythagoras theorem which states as follows;
AC^2 = AB^2 + BC^2
Where AC is the hypotenuse (longest side) and AB and BC are the other two sides
5^2 = 4.5^2 + BC^2
25 = 20.25 + BC^2
Subtract 20.25 from both sides of the equation
4.75 = BC^2
Add the square root sign to both sides of the equation
2.1794 = BC
Rounded up to the nearest tenth, the distance from the hook to the top of the frame will be 2.2 inches
A: 45x + 30y = 1350
Since we don’t know how many adults and children are in the group, we use x and y
b: x-intercept= 30 y-intercept=45
To find the x-intercept you need to isolate the variable. 45x/45 = x
Then you do the same thing to the other side. 1350/45 = 30
So x=30
Same thing with the y-intercept.
30y/30 = y 1350/30 = 45
y=45 (Not really sure what it means by “what they represent” but I thinks it’s that there are 30 adult tickets and 45 children tickets )
c: so our points are (30,0) and (0,45) so you would graph that.
To find how many children tickets were bought if there were 20 adult tickets just look at the photo I put. I don’t know how to explain this.
Hope this helps
Since we don’t know how many adults and children are in the group, we use x and y
b: x-intercept= 30 y-intercept=45
To find the x-intercept you need to isolate the variable. 45x/45 = x
Then you do the same thing to the other side. 1350/45 = 30
So x=30
Same thing with the y-intercept.
30y/30 = y 1350/30 = 45
y=45 (Not really sure what it means by “what they represent” but I thinks it’s that there are 30 adult tickets and 45 children tickets )
c: so our points are (30,0) and (0,45) so you would graph that.
To find how many children tickets were bought if there were 20 adult tickets just look at the photo I put. I don’t know how to explain this.
Hope this helps