The distance between the goals on a soccer field is 52 meters. Each goal has a box that extends 5.49 meters into the field.What
is the distance from the front of the box at one end of the field to the front of the box at the other end of the field?
How can I show my work?
How can I show my work?
1 answer:
Answer:
41.02 meters.
Step-by-step explanation:
See the attached diagram.
The distance between the goals of a soccer field is 52 meters. Each goal has a box that extends 5.49 meters into the field.
If the distance from the front of the box at one end of the field to the front of the box at the other end of the field is x meters, then we can write the equation as
5.49 + x + 5.49 = 52
⇒ x + 10.98 = 52
⇒ x = 41.02 meters. (Answer)
You might be interested in
The equation of the line perpendicular to y = 3x + 6 and containing the point (-9,-5) is
<em><u>Solution:</u></em>
Given that line perpendicular to y = 3x + 6 and containing the point (-9, -5)
We have to find the equation of line
<em><u>The slope intercept form is given as:</u></em>
y = mx + c ------ eqn 1
Where "m" is the slope of line and "c" is the y - intercept
<em><u>Let us first find the slope of line</u></em>
The given equation of line is y = 3x + 6
On comparing the given equation of line y = 3x + 6 with eqn 1, we get,
m = 3
Thus the slope of given equation of line is 3
We know that <em>product of slopes of given line and slope of line perpendicular to given line is equal to -1</em>
Slope of given line slope of line perpendicular to given line = -1
Let us now find the equation of line with slope and containing the point (-9, -5)
Substitute and (x, y) = (-9, -5) in eqn 1
<em><u>Thus the required equation of line is:</u></em>
Substitute and c = -8 in eqn 1
Thus the required equation of line perpendicular to given line is found