Question

HEY GUYS PLEASE HELP ME ANYONE I MEAN ANYONE WHOO EXPLAINS WELL AND NOT FOR THE POINTS WILL BE MARKED AS BRAINLIEST .SOLVE EACH SYSTEM BY SUBSTITUTION SO WE HAVE -4X+6Y=12
X+2Y=-10 SO FAR I GOT -14Y=52 DONT GET ME WONG I KNOW HOW TO SOLVE IT BUT SINCE 14 GOES INTO 52 3 TIMES DO I THEN HAVE TO PLUG IN FOR Y

Answer 1

-4x + 6y = 12
x + 2y = -10

First solve for x in the second equation

x + 2y = -10
x = -10 - 2y

Now we have a value for x so we can substitute it into the other equation

-4 (-10 - 2y) + 6y = 12

Now solve for y

40 + 8y + 6y = 12
40 + 14y = 12
14y = -28
y = -2

Now we have a value for y that we can plug into one of the original equations so we can solve for x

x + 2y = -10
x + 2(-2) = -10
x - 4 = -10
x = -6

Your solution set is

(-6, -2)