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White raven [17]
3 years ago
10

Can someone help me answer this question

Mathematics
1 answer:
ch4aika [34]3 years ago
3 0
What? Need answers. Plus, I can tell that your are doing this in class. Bad idea.
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Find the area of the shaded regions. Give your answer as a completely simplified exact value in terms of π (no approximations).
Anna [14]
The shaded areas add to 2/5 of the area of the circle, which is given by
  A = πr²

Then the shaded area is ...
  (2/5)A = (2/5)π(10 in)²
  shaded area = 40π in²

7 0
3 years ago
A manufacturer fills various size boxes with flour. Today, the boxes are 12 inches tall, 8 inches wide and 3 inches deep. They a
nydimaria [60]
The volume of the box when it's filled to 3 inches deep is 12×8×3 = 288 in³

The box is filled up to 1.5 inches from the top, that means the box is filled only
3-1.5 = 1.5 inches deep

The volume of the box when it's filled to 1.5 inches deep is 12×8×1.5 = 144 in³

The number of flours saved is 288 - 144 = 144 in³
3 0
3 years ago
Read 2 more answers
A letter is chose at random from the word PROGRESSIVENESS.
Vitek1552 [10]

Answer:

2nd option

Step-by-step explanation:

ggggushdhdhdhcghfjf

5 0
3 years ago
PLEASE HELP I DON'T UNDERSTAND! A florist is making regular bouquets and mini bouquets. The florist has 118 roses and 226 peonie
Anna [14]

Answer:

The florist can make 11 regular bouquets and 21 mini bouquets

Step-by-step explanation:

The number of roses the florist has = 118 roses

The number of peonies the florist has = 226 peonies

The number of roses in each regular bouquet = 5 roses

The number of peonies in each regular bouquet = 11 peonies

The number of roses in each mini bouquet = 3 roses

The number of peonies in each mini bouquet = 5 peonies

1. The equation that gives the total number of roses to be used in both kinds of bouquet is given as follows;

Let r represent the number of regular bouquet the florist can make and let m represent the number of mini bouquet the florist can make, we have;

5·r + 3·m = 118...(1)

2. Similarly, we have;

11·r + 5·m  = 226...(2)

Making m the subject of the formula of both equations, and equating both values of m to find a common solution, we have;

m = (118 - 5·r)/3

m = (226 - 11·r)/5

(118 - 5·r)/3 = (226 - 11·r)/5

5 × (118 - 5·r) = 3 × (226 - 11·r)

590 - 25·r = 678 - 33·r

33·r - 25·r = 678 - 590 = 88

8·r = 88

r = 88/8 = 11

r = 11

The number of regular bouquet the florist can make = r = 11

m = (118 - 5·r)/3 = (118 - 5×11)/3 = 21

m = 21

The number of mini bouquet the florist can make = m = 21

The number of regular bouquet the florist can make = 11 bouquets

The number of mini bouquet the florist can make = 21 bouquets.

3 0
2 years ago
What is the standard form of x/4 - y/3 =1 and 5/x - 2/y=7.
kompoz [17]
You can multiply both sides by a number that will get rid of the denominators. For ex. you can multiply the first equation by 12 because 4 and 3 both go into 12 evenly. MAKE SURE YOU MULTIPLY THE OTHER SIDE BY 12 AS WELL! Therefore, 12(x/4) - 12(y/3) = 12(1), or 3x - 4y = 12
5 0
3 years ago
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