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3 years ago

ANYONE PLS HELP ASAP!!!

Mathematics

2 answers:

34kurt3 years ago

7 0

I don’t know I am sorry

ANEK [815]3 years ago

6 0

If Elijah has half a bag of candy and 1 whole bag weighs 5 pounds.
Part A answer- 2.5
Work: 5 divided by 2 which is just 2.5 which is your answer
Part B answer - 12.5
Work- 2 bags = 10 pounds (5x2=10)
We already know half a bag is 2.5 so just add 10+2.5= 12.5

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The image shows three tennis balls enclosed in a cylindrical can. Choose all that are correct. The volume of a single tennis bal

Fynjy0 [20]

Answer:

The volume of a single tennis ball is $14.14\ in^{3}$

The volume of three tennis balls is $42.42\ in^{3}$

Step-by-step explanation:

Step 1

Find the volume of a single tennis ball

we know that

The volume of a sphere is equal to

$V=\frac{4}{3}\pi r^{3}$

where r is the radius of the sphere

In this problem

$r=3/2=1.5\ in$

substitute

$V=\frac{4}{3}\pi (1.5)^{3}$

$V=14.14\ in^{3}$

Step 2

Find the volume of the can

we know that

the volume of the cylinder is equal to

$V=\pi r^{2} h$

where r is the radius of the cylinder

h is the height of the cylinder

in this problem we have

$r=3/2=1.5\ in$

$h=8.4\ in$

substitute

$V=\pi (1.5)^{2}(8.4)$

$V=59.38\ in^{3}$

Statement

case A) The volume of a single tennis ball is $14.14\ in^{3}$

The statement is true

See the procedure in Step 1

case B) The volume of the can is $56.55\ in^{3}$

The statement is false

The volume of the can is $59.38\ in^{3}$ --> see the procedure Step 2

case C) The empty space inside the can is $14.13\ in^{3}$

The statement is false

To find the empty space subtract the volume of three tennis ball from the volume of the can

$59.38\ in^{3}-3*14.14\ in^{3}=16.96\ in^{3}$

case D) The volume of three tennis balls is $42.42\ in^{3}$

The statement is true

To find the volume of three tennis balls multiply the volume of a single tennis ball by three

$14.14*3=42.42\ in^{3}$

8 0

3 years ago

Help me do this i will pick brailest if right and it is 45 points!

sweet-ann [11.9K]

Answer:

8/21

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Which expression is equivalent to *picture attached*

DiKsa [7]

Answer:

The correct option is;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$

Step-by-step explanation:

The given expression is presented as follows;

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right )$

Which can be expanded into the following form;

$\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3 \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left n^2 + 3 \times\sum\limits _{n = 1}^{50} n$

From which we have;

$\sum\limits _{k = 1}^{n} \left k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}$

$\sum\limits _{k = 1}^{n} \left k = \dfrac{n \times (n+1) }{2}$

Therefore, substituting the value of n = 50 we have;

$\sum\limits _{n = 1}^{50} \left k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}$

$\sum\limits _{k = 1}^{50} \left k = \dfrac{50 \times (50+1) }{2}$

Which gives;

$4 \times \sum\limits _{n = 1}^{50} \left n^2 = 4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}$

$3 \times\sum\limits _{n = 1}^{50} n = 3 \times \dfrac{n \times (n+1) }{2} = 3 \times \dfrac{50 \times (51) }{2}$

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3 \times \dfrac{50 \times (51) }{2}$