The table shows y as a function of x. Suppose a point is added to this table. Which choice gives a point that preserves the func
tion? A) (7, 9) B) (2, −1) C) (−8, −3) D) (−6, −2)
2 answers:
Answer:
See explanation
Step-by-step explanation:
Assuming the missing table is the one shown in the attachment,.
For the table to represent a function, none of the first coordinates must repeat.
From the given options, the only point whose first coordinate belong to the table is (-6,-2).
Apart from this point, the other three points can be added to the table and the table will still represent a function.
If this is actually your diagram, then the correct answers are: A) (7, 9) B) (2, −1) C) (−8, −3)
You might be interested in
All the numbers in this range can be written as 
with 
and 
. Construct a table like so (see attached; apparently the environment for constructing tables isn't supported on this site...)
so that each entry in the table corresponds to the sum of the tens digit (row) and the ones digit (column). Now, you want to find the numbers whose digits add to perfect squares, which occurs when the sum of the digits is either of 1, 4, 9, or 16. You'll notice that this happens along some diagonals.
For each number that occupies an entire diagonal in the table, it's easy to see that that number
shows up times in the table, so there is one instance of 1, four of 4, and nine of 9. Meanwhile, 16 shows up only twice due to the constraints of the table.
So there are 16 instances of two digit numbers between 10 and 92 whose digits add to perfect squares.
so that each entry in the table corresponds to the sum of the tens digit (row) and the ones digit (column). Now, you want to find the numbers whose digits add to perfect squares, which occurs when the sum of the digits is either of 1, 4, 9, or 16. You'll notice that this happens along some diagonals.
For each number that occupies an entire diagonal in the table, it's easy to see that that number
So there are 16 instances of two digit numbers between 10 and 92 whose digits add to perfect squares.