A. The scores in order are: 10, 12, 13, 14, 14, 16, 18, 23, 24, 26. The range is 26 - 10 = 16. The mean is the sum divided by 10, which is 17. The median is between 14 & 16, which is 15. The mode is 14, since it is repeated twice.
B. The variance is calculated by subtracting each score from the mean, squaring, and adding all such squares. Then divide by the number of terms (10) to get 27.6 Take the square root to get the standard deviation, which is 5.25.
C. This is for a population, since these are all 10 games that Jason played. (If it were a sample, we would divide by 9 only)
D. The mean of 17 is higher than the median of 15 and the mode of 14. This implies a left-skewed distribution. However, the SD of 5.25 is quite high relative to the mean of 17, so the distribution is not that clearly defined yet (more data points would make it clearer).
Answer:
Step-by-step explanation:
Given a rectangular tank with dimension (10ft by 20ft by 16ft)
Then the volume of the tank is
Volume =length × breadth ×height
Volume=10×20×16=3200ft³
V=3200ft³
Then,
∆F= weight density × volume
∆F= 62.4×3200
∆F= 199,680 lb
Then,
Let the 0-point on the x-axis be at the bottom of the tank, so the level of the water ranges from x = 0 to x = 16ft. (It would just as well to let 0 be ground level and let x range from x = −26ft to x − 0.) Then a slice of water at level x is raised (26− x)ft
Then ∆x=(26-x)ft
Work is given as
W= -∫F∆xdx. From 0 to 16
W= -∫199,680(26-x)dx From 0 to 16
W=-199,680∫26-x dx From 0 to 16
W=-199,680 (26x-x²/2). From 0 to 16
W=-199,680(26×16-0.5×16² -0-0)
W=-199,680(288)
W=-57,507,840J
The work done to empty the tank is 57,507,840J
the answer is c
this is because, first you use the distributive property. Multiply 'y' by the number 3 and you get 3y
then multiply 3 by the number 4.
you get 12
subtract 7 from 12 and you get 5
So, the expression becomes 3y+5
Hope this helped!!
Data points
a data series
an x axis
a y axis
a legend
hope this helps (: