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Ivenika [448]
3 years ago
13

Write this number in standard form 4^3 x 5^0

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
8 0
<span>4^3x5^0
</span>
<span><span>(<span>4^3</span>)</span><span>(<span>x<span>5^0</span></span>)</span></span>
=64x

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Which trinomial is the product of the expression below ? (2R-3) (R+12)
anastassius [24]
Answer:
2R^2 + 21R - 36

Explanation:
To answer this question, we will follow these steps:
1- expand the brackets
2- gather like terms

Steps are as follows:
(2R-3)(R+12) = 2R(R) + 2R(12) - 3(R) - 3(12)
                      = 2R^2 + 24R - 3R - 36
                      = 2R^2 + 21R - 36

Hope this helps :)

8 0
3 years ago
Read 2 more answers
Can someone Please help me if you’re correct I’ll give Brainlist!
kipiarov [429]

Answer:

x=75

Step-by-step explanation:

The triangle is isosceles, meaning that the angles V and U are congruent

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3 years ago
What is the end behavior of the function f(x) = 3x4−x3 + 2x2 + 4x + 5? (1 point)
ELEN [110]

Answer: both the left and right sides go to +∞

<u>Step-by-step explanation:</u>

End behavior can be determined by two things:

  • Sign of the leading coefficient
  • Degree of the function

<u>Sign of leading coefficient</u>:

positive: right side goes to +∞

negative: right side goes to -∞

⇒ Leading coefficient of this function is 3 so the right side goes to +∞

<u>Degree (exponent of leading coefficient)</u>:

even: both the left and right sides point in the SAME direction

odd: the left and right sides point in OPPOSITE directions

⇒ Degree of this function is 4 so the left side will point in the same direction as the right side.

8 0
3 years ago
Use the zero product property to find the solution to the equation x^2 +12=7x
pochemuha
X2 + 12 = 7x x2 – 7x + 12 = 0factor the equation (x – 3 ) ( x – 4 ) = 0 Then equating both factor to 0 X – 3 = 0 X = 3 And X – 4 = 0 X = 4 So the answer is X = 3 X =4 
6 0
3 years ago
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. An object dropped from a height of 200 meters has a height, h(t), in meters after t seconds have lapsed, such that h(t) = 200
Veronika [31]

Answer:

t(h)= (h-200)/-4.9

The time to reach a height of 50 meters is 30.6 seconds

Step-by-step explanation:

To express t as a function of height (h) we must transform the equation below:

h=200-4.9t

h-200=-4.9t

(h-200)/-4.9=t

t(h)= (h-200)/-4.9

To find the time to reach a height of 50 meters, we must replace this value on the new equation:

t(h)=50-200/-4.9

t(h)= 30.612

The time to reach a height of 50 meters is 30.6 seconds

8 0
3 years ago
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