Locate 1 on the x axis. This is the horizontal number line.
Draw a vertical line through 1 on the x axis. Extend this vertical line as far up and down as you can.
Notice how the vertical line crosses the blue curve. Mark this point. Then draw a horizontal line from this point to the y axis. The horizontal line will touch -4 on the y axis. So that means the point (1,-4) is on the curve.
If the input it is x = 1, then the output is y = -4
So that's why the answer is choice A
For the P=-4
what you do is subtracting 6 to the 38 you will have -8p=32 then you will divide-8 to both sides and your answer will be p=-4
check 6-8(-4)=38
6+32=38
38=38
i got K=5.6
what you do is add 13 to the 15 and you will have 28=5k then you will divide 5 to both sides and you will have k=5.6
check 15=5(5.6)-13
15=28-13
15=15
There are two possible answers: 72 and 90.
We can find the answer by looking at the largest number among the three of them: 18. The only multiples of 18 between 61 and 107 are 72 and 90. We can check that both numbers are also multiples of 6 and 9:
90 : 6 = 15
90 : 9 = 10
72 : 6 = 12
72 : 9 = 8
Answer:
LCD of 7 and 5 is 35
Step-by-step explanation:
In many cases, you can find the lowest common denominator by simply multiplying the two numbers together. This method works in your example.
7 x 5 = 35
The two fractions would become 15/35 and 28/35
There will be times when this will not get you straight to the answer, eg find the lowest common denominator of 8 and 12. For this you need to list some multiples of the numbers until you get a number which appears in both lists:
8: 8, 16, 24
12: 12, 24
So, the lowest common denominator of 8 and 12 is 24.
Check the picture below.
let's notice the "white" ∡1 is an inscribed angle with an intercepted arc of (x-32), and the "green" ∡5 is also an inscribed angle with an intercepted arc of (2x).
the ∡6 and ∡2 are both external angles, however they intercepted two arcs, a "far arc" and a "near arc", thus we'll use the far arc - near arc formula, as you see in the picture, and we'll use the inscribed angle theorem for the other two.
![\bf \measuredangle 1=\cfrac{x-32}{2}\implies \measuredangle 1 =\cfrac{32}{2}\implies \measuredangle 1 = 16 \\\\[-0.35em] ~\dotfill\\\\ \measuredangle 5 =\cfrac{2x}{2}\implies \measuredangle 5 = x\implies \measuredangle 5 = 64 \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cmeasuredangle%201%3D%5Ccfrac%7Bx-32%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%201%20%3D%5Ccfrac%7B32%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%201%20%3D%2016%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cmeasuredangle%205%20%3D%5Ccfrac%7B2x%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%205%20%3D%20x%5Cimplies%20%5Cmeasuredangle%205%20%3D%2064%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf \measuredangle 2 = \cfrac{(2x+8)~~-~~(x-32)}{2}\implies \measuredangle 2=\cfrac{2x+8-x+32}{2} \\\\\\ \measuredangle 2=\cfrac{x+40}{2}\implies \measuredangle 2=\cfrac{104}{2}\implies \measuredangle 2=52 \\\\[-0.35em] ~\dotfill\\\\ \measuredangle 6=\cfrac{[(2x+8)+(x)]~~-~~(2x)}{2}\implies \measuredangle 6=\cfrac{3x+8-2x}{2}\implies \measuredangle 6=\cfrac{x+8}{2} \\\\\\ \measuredangle 6=\cfrac{72}{2}\implies \measuredangle 6=36](https://tex.z-dn.net/?f=%5Cbf%20%5Cmeasuredangle%202%20%3D%20%5Ccfrac%7B%282x%2B8%29~~-~~%28x-32%29%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%202%3D%5Ccfrac%7B2x%2B8-x%2B32%7D%7B2%7D%20%5C%5C%5C%5C%5C%5C%20%5Cmeasuredangle%202%3D%5Ccfrac%7Bx%2B40%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%202%3D%5Ccfrac%7B104%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%202%3D52%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cmeasuredangle%206%3D%5Ccfrac%7B%5B%282x%2B8%29%2B%28x%29%5D~~-~~%282x%29%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%206%3D%5Ccfrac%7B3x%2B8-2x%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%206%3D%5Ccfrac%7Bx%2B8%7D%7B2%7D%20%5C%5C%5C%5C%5C%5C%20%5Cmeasuredangle%206%3D%5Ccfrac%7B72%7D%7B2%7D%5Cimplies%20%5Cmeasuredangle%206%3D36)
