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andreyandreev [35.5K]
3 years ago
12

Find the area of the triangle 14cm 25cm

Mathematics
1 answer:
Anna71 [15]3 years ago
4 0

Answer:

175 cm

Step-by-step explanation:

assuming it's a right triangle, the formula used is A= (1/2)(base)(height)

so (1/2)(14)(25)

which equals 175

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Step-by-step explanation:

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Find the length of the missing side of the right triangle 15 and 9 Round your answer to the nearest tenth, if necessary.
mamaluj [8]

Answer:

17.5

Step-by-step explanation:

a^2+b^2=c^2

15^2+9^2=306^2

square root of 306= 17.49

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3 years ago
Complete the equation to represent finding x, the greater integer.<br><br> x(x – ) = 143
mart [117]

Answer:

x would equal -11 or 13

Step-by-step Explanation:

x(x - 2) - 143 = 0

x^2 - 2x - 143 = 0

-2x + x^2 = 143

-143 + (-2x) + x^2 = 0

(x - 13)(x + 11)

x - 13 = 0

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x = 13

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3 0
3 years ago
The caller times at a customer service center has an exponential distribution with an average of 22 seconds. Find the probabilit
jenyasd209 [6]

Answer:

The probability that a randomly selected call time will be less than 30 seconds is 0.7443.

Step-by-step explanation:

We are given that the caller times at a customer service center has an exponential distribution with an average of 22 seconds.

Let X = caller times at a customer service center

The probability distribution (pdf) of the exponential distribution is given by;

f(x) = \lambda e^{-\lambda x} ; x > 0

Here, \lambda = exponential parameter

Now, the mean of the exponential distribution is given by;

Mean =  \frac{1}{\lambda}  

So,  22=\frac{1}{\lambda}  ⇒ \lambda=\frac{1}{22}

SO, X ~ Exp(\lambda=\frac{1}{22})  

To find the given probability we will use cumulative distribution function (cdf) of the exponential distribution, i.e;

    P(X\leq x) = 1 - e^{-\lambda x}  ; x > 0

Now, the probability that a randomly selected call time will be less than 30 seconds is given by = P(X < 30 seconds)

        P(X < 30)  =  1 - e^{-\frac{1}{22} \times 30}

                         =  1 - 0.2557

                         =  0.7443

7 0
4 years ago
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