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S_A_V [24]
3 years ago
9

If f(x) = V7x + 31 , find f(0).

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
3 0

Answer:

f(0) = 31

Step-by-step explanation:

We are given the following function:

f(x) = \sqrt{7x} + 31

f(0).

This is the value of f when x = 0. So

f(0) = \sqrt{7*0} + 31 = \sqrt{0} + 31 = 0 + 31 = 31

So f(0) = 31

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The perimeter of a square P depends on the length of its sides S this can be written in function notation as P( s) what is the b
IrinaK [193]

Answer:

sorry I don't know

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5 0
2 years ago
The function y = f(x) is graphed below. What is the average rate of change of the
Serjik [45]

The average rate of change of the function in the given interval -3 ≤ x ≤-1 is 10.

<h3>What is the average rate of change?</h3>

The average Rate of Change of the function f(x) can be calculated as;

f(x) = \dfrac{f(b) - f(a)}{b-a}

Interval -3 ≤ x ≤-1

a = -3, b = -1

f(a) = f(-3) = -20

f(b) = f(-1) = 0

Step 2: Find Average

f(x) = \dfrac{f(b) - f(a)}{b-a}\\\\\\f(x) = \dfrac{f(-1) - f(-3)}{-1-(-3)}\\\\\\f(x) = \dfrac{0 - (-20)}{2}\\\\f(x) = 10

Therefore, the average rate of change of the function in the given interval -3 ≤ x ≤-1 is 10.

Learn more about average rate;

brainly.com/question/20784578

#SPJ1                  

3 0
1 year ago
PLEASE PLEASE HELP! Find the measure of APB^.
Whitepunk [10]

Answer:

65°

Step-by-step explanation:

Radii CA and CB are perpendicular to tangent lines AT and BT, so

\angle CAT=\angle CBT=90^{\circ}

Since angle BAT is equal to 65°, angle CAB has measure

\angle CAB=90^{\circ}-65^{\circ}=25^{\circ}.

Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus

\angle CBA=\angle CAB=25^{\circ}

The sum of the measures of all interior angles in triangle is always 180°, so

\angle CAB+\angle CBA+\angle ACB=180^{\circ}\\ \\25^{\circ}+25^{\circ}+\angle ACB=180^{\circ}\\ \\\angle ACB=130^{\circ}

Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so

x=\angle APB=\dfrac{1}{2}\cdot 130^{\circ}=65^{\circ}

8 0
3 years ago
HELP ME !!!!!!!!!!!!!!!!!!!!!!!!!!
gogolik [260]

Answer:

Bye

Step-by-step explanation:

Figure it out yourself

4 0
3 years ago
Who can help me?<br>please<br>Thank you​
4vir4ik [10]

The sum of the interior triangles in a triangle is 180, so if we add all the angle measures together, we should get 180. Therefore, we can make an equation like this,

110-2x+x+50+5x-40=180

Simplify this.

4x+120=180

4x=60

x=15

Now we can find each angle measure.

110-2x

110-2(15)

110-30

80

x+50

15+50

65

5x-40

5(15)-40

75-40

35

So the angle labeled 110-2x is the largest angle in the triangle.

7 0
3 years ago
Read 2 more answers
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