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Alexus [3.1K]
3 years ago
14

Plot the graphs of the given linear equations x-3y=0 ANSWER ASAP PLEASE!

Mathematics
1 answer:
Nikitich [7]3 years ago
5 0

Answer:

Refer to attached

Step-by-step explanation:

  • x-3y=0

Graph is attached

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What is the midpoint between -2-3i and 3+9i
Svetlanka [38]

Answer:

1/2 + 3i is the midpoint between -2-3i and 3+9i.

Step-by-step explanation:

Given the complex number

  • -2-3i
  • 3+9i

The formula to find the midpoint of two complex number (a + bi) and (c + di) is:

M=\frac{\left(a+c\right)}{2}+\frac{\left(b+d\right)i}{2}

M=\frac{\left(-2+3\right)}{2}+\frac{\left(-3+\left(9\right)\right)i}{2}

M=\frac{-2+3+\left(-3+9\right)i}{2}

M=\frac{1+6i}{2}

M=\frac{1}{2}+3i

Therefore, 1/2 + 3i is the midpoint between -2-3i and 3+9i.

3 0
3 years ago
How many $1 dollar bills do i need to circle the earth? Thanks
ozzi
1 billion dollars × 6 inches per dollar = 6 billion inches / 63,360 inches per mile = 94,636.97 miles coverted by1 billion bills. answer = 94,636.97 miles 
8 0
4 years ago
Dee’s clothing is having a discount of 40% on all shirts. Let x represent the regular price of any shirt in the store. Write an
Luden [163]
S=shirt and P=price x=reg price so x-s I think
6 0
4 years ago
Read 2 more answers
Graph the line x=-3
Nuetrik [128]
I think you would put an x on the -3 on a number line idk but yeahhh
7 0
4 years ago
Read 2 more answers
Please help with the questions in the image
iren2701 [21]

Step-by-step explanation:

This seems to be calculus 1.

<u>Question a</u>

We have -2x^3 + 5x^2 + 9

m = slope = derivative

Find the derivative / slope of -2x^3 + 5x^2 + 9

We do this by differentiating the polynomials. There are a few methods to do this but I am going to use the power rule, which we multiply the constant by the exponent on the variable and subtract one from the exponent.

\frac{d}{dx}(-2x^3 + 5x^2 + 9)

-6x^2 + 10x

m = -6x^2 + 10x when x = a

<em>Now that we have this information, we can answer question b</em>

<u>Question b</u>

<u>The tangent line for Point (1, 12)</u>

First find the slope by using our derivative.

m = -6x^2 + 10x

m = -6(1)^2 + 10(1)

m = -6 + 10x

m = 4

Now that we have our slope, use point slope form to find our tangent line

y - 12 = 4(x - 1)

y(x) = 4x + 8


<u>Now lets do the same for the Point (2, 13)</u>

Find the slope at the point.

m = -6x^2 + 10x

m = -6(2)^2 + 10(2)

m = -24 + 10

m = -4

Now find the tangent line using point slope form of a line.

y(x) - 13 = -4(x - 2)

y(x) = -4x + 21


Now graph the lines, which I have done and you can see by viewing the image I have attached.


6 0
4 years ago
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