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Lelu [443]
3 years ago
13

EASY MATH!(WILL BRAINLIEST TO FIRST TO ANSWER) HELP! :3

Mathematics
2 answers:
sergejj [24]3 years ago
5 0
The answer is A because at x = 1 y = -4.
Tasya [4]3 years ago
4 0

The answer is A) -4 .......

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Which is the best estimate of -14 1/9(-2 9/10)?<br> O-42<br> O -28<br> O 28<br> O42
pashok25 [27]

Answer:

The best estimate for the given calculation is 2.8.

Step-by-step explanation:

To determine the correct option regarding the result of this calculation, the mathematical resolution of the same must be developed:

-14 x 1 /9 x (-2 x 9/10) = X

-14 x 1 / 9 x (-18 / 10) = X

-14 x 1 / 9 x -1.8 = X

-14 / 9 x -1.8 = X

-1.555555 x -1.8 = X

2.8 = X

Therefore, the best estimate result for this mathematical operation is 2.8.

5 0
3 years ago
Select all of the following true statements if R = real numbers, Z = integers, and W = {0, 1, 2, ...}
scoundrel [369]
We can start solving this problem by first identifying what the elements of the sets really are.

R is composed of real numbers. This means that all numbers, whether rational or not, are included in this set.

Z is composed of integers. Integers include all negative and positive numbers as well as zero (it is essentially a set of whole numbers as well as their negated values).

W on the other hand has 0,1,2, and onward as its elements. These numbers are known as whole numbers.

W ⊂ Z: TRUE. As mentioned earlier, Z includes all whole numbers thus W is a subset of it.

R ⊂ W: FALSE. Not all real numbers are whole numbers. Whole numbers must be rational and expressed without fractions. Some real numbers do not meet this criteria.

0 ∈ Z: TRUE. Zero is indeed an integer thus it is an element of Z.

∅ ⊂ R: TRUE. A null set is a subset of R, and in fact every set in general. There are no elements in a null set thus making it automatically a subset of any non-empty set by definition (since NONE of its elements are not an element of R).

{0,1,2,...} ⊆ W: TRUE. The set on the left is exactly what is defined on the problem statement for W. (The bar below the subset symbol just means that the subset is not strict, therefore the set on the left can be equal to the set on the right. Without it, the statement would be false since a strict subset requires that the two sets should not be equal).

-2 ∈ W: FALSE. W is just composed of whole numbers and not of its negated counterparts.
5 0
4 years ago
Read 2 more answers
8. The talent show committee sold a total of 530 tickets in advance. Student
Alex Ar [27]

Answer:

Number of students tickets sold = x = 380 tickets

Number of adults tickets sold = y = 150 tickets

Step-by-step explanation:

Let

Number of students tickets sold = x

Number of adults tickets sold = y

x + y = 530 (1)

3x + 4y = 1740 (2)

From (1)

x = 530 - y

Substitute x = 530 - y into (2)

3x + 4y = 1740

3(530 - y) + 4y = 1740

1590 - 3y + 4y = 1740

- 3y + 4y = 1740 - 1590

y = 150

Substitute y = 150 into (1)

x + y = 530

x + 150 = 530

x = 530 - 150

x = 380

Number of students tickets sold = x = 380 tickets

Number of adults tickets sold = y = 150 tickets

3 0
3 years ago
In the rhombus, m∠1=8y-6. Find the value of y?
lesya [120]

Answer:

The value of y = 12

Step-by-step explanation:

<u>Points to remember </u>

In a rhombus the diagonals are bisect each other perpendicularly.

<u>To find the value of y</u>

From the figure we can see a rhombus. The <1 is a right angle.

m<1 = 90

Therefore,  8y - 6 = 90°

8y = 90  + 6

8y = 96

y = 86/8

y = 12

Therefore the value of y = 12

8 0
3 years ago
Law of sines and cosines word problem
marishachu [46]

Answer:

AC = 0.47 mi

BC = 0.51 mi

Step-by-step explanation:

Notice that we are in the case of an acute triangle for which we know two angles ( < A = 63 and < B = 56) and one side (AB = 0.5).

We can find the measure of the third angle using the property of addition of three internal angles of a triangle:

< A + < B + < C = 180

63 + 56 + < C = 180 degrees

< C = 180 - 63 - 56 = 61 degrees.

Now we use the law of sines to find the length of sides AC  and BC:

\frac{0.5}{sin(61)} =\frac{AC}{sin(56)}\\AC=\frac{0.5*sin(56)}{sin(61)} \\AC\approx 0.4739\,\,\,mi

which can be rounded to two decimals as:

AC = 0.47mi

For side BC we use:

\frac{0.5}{sin(61)} =\frac{BC}{sin(63)}\\BC=\frac{0.5*sin(63)}{sin(61)} \\BC\approx 0.509\,\,\,mi

which can be rounded to two decimals as:

BC = 0.51 mi

6 0
3 years ago
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