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3 years ago

How do you calculate the residuals for a scatterplot?

2 answers:

dsp733 years ago

7 0

To find the residual I would subtract the predicted value from the measured value so for x-value 1 the residual would be 2-2.6 = -0.6

Ivanshal [37]3 years ago

3 0

To find the residual I would subtract the predicted value from the measured value for x-value.

Step-by-step explanation:

Read more about distances at:

brainly.com/question/12961022

6 0

2 years ago

Hey does anyone know?

prisoha [69]

The coordinates for M is (4,5)

6 0

3 years ago

William has a 26-liter glass tank. First, he wants to put some marbles into it, all of the same volume. Then, he wants to fill t

ELEN [110]

Snejiejcjdjdkxmxmxmcm j ncmmcmdmeme

8 0

3 years ago

M+2/3=1/4m-1 what the formula used to find the value of m?

zimovet [89]

Answer:

The value of m is $\frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6}$ by using quadratic formula

Solution:

Given, expression is $m+\frac{2}{3}=\frac{1}{4 m}-1$

Now, we have to solve the above given expression.

$\text { Now, } \mathrm{m}+\frac{2}{3}=\frac{1}{4 m}-1$

By multiplying the equation with m, we get

$\begin{array}{l}{m^{2}+\frac{2}{3} m+m=\frac{1}{4}} \\\\ {m^{2}+m\left(\frac{2}{3}+1\right)=\frac{1}{4}} \\\\ {m^{2}+\frac{5}{3} m=\frac{1}{4}}\end{array}$

$\begin{array}{l}{12 m^{2}+20 m=3} \\ {12 m^{2}+20 m-3=0}\end{array}$

Now, let us use quadratic formula

$\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in our problem, a = 12, b = 20, c = -3

$\begin{array}{l}{m=\frac{-20 \pm \sqrt{20^{2}-4 \times 12 \times(-3)}}{2 \times 12}} \\\\ {=\frac{-20 \pm \sqrt{400+144}}{24}} \\\\ {=\frac{-20 \pm \sqrt{544}}{24}} \\\\ {=\frac{-20 \pm 4 \sqrt{34}}{24}=\frac{-5 \pm \sqrt{34}}{6}} \\\\ {=\frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6}}\end{array}$

Hence the value of m is $\frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6}$ by using quadratic formula

7 0

3 years ago

Round the number 347500 to the nearest 1000

tatyana61 [14]

Answer:

348000

Step-by-step explanation:

The place you want to round to is the thousands place. The place to the right of that is the hundreds place. If the digit in the hundreds place is 5 or more (and it is), then the rounded number will have 1 added to its thousands digit.

After making that adjustment (if necessary), all digits to the right (hundreds, tens, ones, and so on) will be set to zero.

_____

Comment on rounding

Various rounding schemes are in use. The one described above is the one usually taught in school. In real life, it has the disadvantage that it can add a bias to a set of numbers, making their total come out higher than desired. In order to counter that, a "round to even" rule is sometimes used.

In this problem, that would mean the thousands digit would only be changed on the condition it would be changed to an even digit. (Here, that rule would give the same result. The number 346500 would be rounded down to 346000, for example.)

Various spreadsheets and computer programs implement different rounding schemes, depending on the application and the amount of bias that is tolerable. So, you may run across one that seems to be "wrong" according to what you learned in school.

6 0

3 years ago