3 years ago

How do i do this equation -3(-2y-4)-5y-2=

1 answer:

3 0

Answer:

Step-by-step explanation: distribute -3 to the parenthesis (-2y-4) to eliminate the parenthesis. you’ll be left with 6y +12 -5y-2. From there you combine like terms. do 6y-5y= 1y or just y and 12-2 = 10. your answer would be 10

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Complete the square on the following quadratic x2+10x+9=0

kakasveta [241]

Given a quadratic equation $x^{2} +ax+c=0$

1. the first thing we do when we want to compete the square, is write the coefficient of x as 2 times a number.

In our case the coefficient of x is 10, so we write 10 as 2*5

2. then we write + $5^{2}$ and - $5^{2}$ to the expression:

$x^{2} +2*5*x+ 5^{2} -5^{2}+9=0$

$(x^{2} +2*5*x+ 5^{2}) -25+9=0$

$(x+5)^{2}-16=0$

Answer: $(x+5)^{2}-16=0$

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3 years ago

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Mila [183]

Answer:

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3 years ago

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